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Quantitative Aptitude Test - 15

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Quantitative Aptitude Test - 15
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  • Question 1
    1 / -0.25

    Compare the two quantities in A and B.

    Quantity A: 50% of 40% of 100

    Quantity B: 45% of 45% of 100

    Solution
    Quantity \(A: \frac{50}{100} \times \frac{40}{100} \times 100=20\)
    Quantity \(B: \frac{45}{100} \times \frac{45}{100} \times 100=20.25\)
    Hence, the correct option is (b).
  • Question 2
    1 / -0.25

    A candidate who gets 20% marks fails by 10% marks, but another candidate who gets 42% marks gets 12 marks more than the passing marks. Find the maximum marks?

    Solution
    Let the maximum marks be x.
    I. Passing marks \(=\frac{20 x}{100}+\frac{10 x}{100}=\frac{30 x}{100}\)
    II. Marks obtained by another student \(=\frac{42}{100} \mathrm{x}\)
    Now, according to the question, \(\frac{42 x}{100}-\frac{30 x}{100}=12\)
    \(\frac{12 x}{100}=12\)
    \(x=100\)
    Hence, the correct option is (b).
  • Question 3
    1 / -0.25

    A motorboat can travel at a speed of 9 km/hr. It takes twice the time to travel upstream than to travel downstream. Find out the rate of flow of the stream.

    Solution
    According to the question,
    \(\frac{\text { Time taken in up stream }}{\text { Time taken in dowstream }}=\frac{2}{1}\)
    \(\frac{\text { Downstream speed }}{\text { Upstream speed }}=\frac{2}{1}\)
    If the speed of boat in still water is \(S\) and the rate of flow of stream is \(T,\) then
    \(\frac{S+T}{S-T}=\frac{2}{1}\)
    Or \(\frac{S}{T}=\frac{3}{1}\)
    Or \(\frac{9}{T}=3\) (Speed of boat in still water is \(9 \mathrm{km} / \mathrm{hr}\) )
    Or \(\mathrm{T}=3 \mathrm{km} / \mathrm{hr}\)
    Rate of flow of stream \(=3 \mathrm{km} / \mathrm{hr}\)
    Hence, the correct option is (a).
  • Question 4
    1 / -0.25

    Compare the two quantities in A and B.

    Quantity A

    Probability of getting & Probability of getting sum as an even number when two dice are rolled & when two dice are rolled together .

    Quantity B

    Probability of getting & Probability of getting sum as an odd number when two dice are rolled & when two dice are rolled together .

    Solution

    Quantity A:
    Favourable cases = (1, 1), (1, 3), (2, 2), (3, 1), (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), (4, 6), (5, 5), (6, 4), (6, 6) = 18 in number

    Total outcomes = 36So,

    required probability = 1836
    Quantity B:

    Favourable cases = (1, 2), (2, 1), (1, 4), (2, 3), (3, 2), (4, 1), (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1), (3, 6), (4, 5), (5, 4), (6, 3), (5, 6), (6, 5) = 18 in number

    Total outcomes = 36

    So, required probability = 1836

    Thus, quantity A = quantity B

    Hence, the correct option is (c).

  • Question 5
    1 / -0.25

    Aditya can finish a piece of work in 21 days and Sam can do the same work in 24 days. They start the work together but after some time, Aditya leaves the work and Sam finishes it in 9 days. Find out after how many days Aditya left the work?

    Solution
    Let Aditya leave the work after \(x\) days. Then
    Equation as follows
    \(\Rightarrow \frac{15 x}{168}=\frac{15}{24}\)
    \(\Rightarrow x = \frac{15}{24}\times\frac{168}{15}\)
    \(\Rightarrow x=7.\)
    Hence, the correct option is (c).
  • Question 6
    1 / -0.25

    Directions For Questions

    The question below consists of a question stem and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

    ...view full instructions

    Eight friends A, B, C, D, E, F, G and H are sitting around a circular table with four facing outside and four facing towards the centre and each one of them like different colours pink, blue, black, white, brown, green, yellow and orange, but not necessarily in the same order. No two neighbours are sitting facing in the same direction. Who likes black colour?

    I. D and E are sitting together and like the colour starting with the same alphabet. E is sitting opposite to B.

    II. F is not facing outside and is neither the neighbour if D nor E. Person who likes brown colour does neither sit with D nor with E.

    Solution

    From statement I, it is known that out of D and E, either one of the person likes black or brown or blue and from statement II, it is known that neither D nor E likes brown colour. But still it is not known even from both the statements that who likes black colour. So, both the statements taken together are not sufficient to answer the question.

    Hence, the correct option is (a).

  • Question 7
    1 / -0.25

    Directions For Questions

    The question below consists of a question stem and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

    ...view full instructions

    Six friends P, Q, R, S, T and U are sitting in a row facing towards north, but not necessarily in the same order. Who is sitting on the extreme right?

    I. P and U are not sitting together. R is sitting second to the right of Q and S is sitting second to the right of T.

    II. There are two persons sitting between T and R and also two persons are sitting between Q and U.

    Solution

    From statement I, arrangement is such that Q_R and T_S.

    From statement II, arrangement is T _ _ R or R _ _ T and Q _ _ U or U _ _ Q.

    On combining both the statements, we get the arrangement as P T Q S R U.

    So, both the statements I and II taken together are sufficient to answer the question.

    Hence, the correct option is (c).

  • Question 8
    1 / -0.25

    Directions For Questions

    The question below consists of a question stem and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

    ...view full instructions

    There are ten members in the family out of which three are married couples, 5 males and 5 females. How many grandsons does B have?

    I. M is married to N, who is B’s son. P has two sons and only one brother who is married to M and M does not have any son.

    II. B is married to A and has one son and one daughter who are married.

    Solution

    From statement I, following arrangement has been obtained:

    As P has only one brother, who does not have any son, so, it can be determined that B has two Grandsons.

    Hence, the correct option is (d).

  • Question 9
    1 / -0.25

    Directions For Questions

    The question below consists of a question stem and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

    ...view full instructions

    A panel of scientists ranked eight researchers – Jacob, Emily, Chloe, Ifaz, Jack, Robert, Lilly and Ela – according to the results obtained from their researches. No other researchers were considered and there were no ties in the final ranking. Who was ranked as the highest?

    I. Robert was ranked higher than Jacob but lower than Jack. Jack was not ranked as the highest. Three researchers were ranked lower than Emily. Lilly was ranked higher than Ela but lower than Chloe.

    II. Jacob was ranked lower than three researchers. Emily was ranked lower than Jacob but higher than Chloe and Lilly. Jack was ranked as the second highest.

    Solution

    From both the statements I and II, arrangement obtained is such that Ifaz > Jack > Robert > Jacob > Emily > Chloe > Lilly > Ela.

    So, both the statements I and II taken together are sufficient to answer the question.

    Hence, the correct option is (c).

  • Question 10
    1 / -0.25

    Directions For Questions

    The question below consists of a question stem and two statements numbered I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

    ...view full instructions

    Seven sessions abbreviated as P, Q, R, S, T, U and V are scheduled each for an hour consecutively in a same day, but not necessarily in the same order. No two sessions are scheduled in the same period of time. Which session is scheduled in the last?

    I. P and R are scheduled consecutively one after another but none of them is scheduled in the ends. Two sessions are scheduled after session T. Three sessions are scheduled between P and V and two sessions are scheduled between Q and T.

    II. R is scheduled as the fourth session. Session T is scheduled before V and after R. Session U is scheduled after S but not in the last and P and Q are scheduled together.

    Solution

    Session Number

    From Statement I

    From Statement II

    From Statement III

    1

    U/S

    P/Q/S

    P/Q/S

    2

    Q

    P/Q/S

    P/Q/S

    3

    P

    P/Q/S

    P/Q/S

    4

    R

    R

    R

    5

    T

    U

    T

    6

    U/S

    T

    U

    7

    V

    V

    V

    Using any of the statement we can conclude that session \(\mathrm{V}\) is the last.
    Hence, the correct option is (d).
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