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Quantitative Aptitude Test - 2

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Quantitative Aptitude Test - 2
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  • Question 1
    1 / -0.25

    Directions For Questions

    Directions: Use the following chart, which represents the value of exports and imports (in Rs hundred crore) of a country for a certain period, to answer the given question.

    ...view full instructions

    What percentage is the total export in the years 2003, 2006 and 2008 taken together of the total import for the same period?

    Solution
    Total exports in 2003, 2006 and 2008 = 150 + 300 + 175 = 625
    And imports in same year = 75 + 225 +275 = 575
    Now, required % = 625 x 100575 = 108.6% ~ 109%.
    Hence, the correct option is (a).
  • Question 2
    1 / -0.25

    Giri divided his property between his children Suma and Dev. Suma invested her share at 10% per annum simple interest and Dev invested his share compounded at 8% per annum. At the end of 2 years, the interest received by Suma is Rs 13,360 more than the interest received by Dev. What was Suma's share if the total amount divided was Rs 2,50,000?

    Solution
    Let’s say Dev’s share is Rs s.
    Then Suma gets Rs (250000 – s)
    Interest received by Dev compounded at 8% for 2 years:
    = s[1 + 8100]2 – s= (2725)2 s – s = 104 s625
    Interest received by Suma at 10% per annum simple interest would be
    =(250000–s) x 10 x 2100 = (250000s)5
    (250000s)5 = 104 s625 + 13,36
    Implies 625 (250000 – s) = 5 (104s + 625 x 13360); or s = Rs 1,00,000
    Hence Suma’s share = Rs 1,50,000.
    Hence, the correct option is (d).
  • Question 3
    1 / -0.25

    At a factory, 3 fully automatic printing machines working together required 43 days to print a certain number of pages. When 4 semi-automatic printing machines worked together, they also required 43 days to print the same number of pages. If the factory had 7 fully automatic printing machines and 5 semi-automatic printing machines and they all worked together, what would be the total number of days they would require to print the same number of pages?

    Solution

    3 fully automatic printing machines required 43 days to print a certain number of pages.
    Therefore, 1 fully automatic printing machine would print 1(43 × 3) pages in a day.
    Similarly, 1 semi-automatic printing machine would print 1(43 × 4) pages in a day.
    7 fully automatic printing machines and 5 semi-automatic printing machines would print 7(43 × 3) + 5(43 × 4) = 112 of the pages in 1 day.
    Therefore, 7 fully automatic printing machines and 5 semi-automatic printing machines would print all the pages in 12 days.

    Hence, the correct option is (d).
  • Question 4
    1 / -0.25

    The front wheel of a bus has a circumference of 137 cm, while the rear wheel has a circumference of 173 cm. If each front wheels makes 108 revolutions more than each rear wheel, what is the total distance that the bus travels?
    Note: Assume that each wheel completes an integral number of revolutions.

    Solution
    The result has to be multiple of 137 and 173. Checking option-wise:
    137 × 173 = 23,701
    137 × 173 × 2 = 47,402
    137 × 173 × 3 = 71,103
    137 × 173 × 4 = 94,804
    137 × 173 × 8 = 1,89,608
    Choosing 23,701, each front wheel will take 173 revolutions and each rear wheel will take 137 revolutions.
    Difference = 173 – 137 = 36
    Choosing 47,402, each front wheel will take 346 revolutions and each rear wheel will take 274 revolutions.
    Difference = 72
    Choosing 71,103, each front wheel will take 519 revolutions and each rear wheel will take 411 revolutions.
    Difference = 108.
    Hence, the correct option is (c).
  • Question 5
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    A vendor buys 10 metal pieces each at the same price but he sells them at different prices each. He decides the selling price of each piece as follows. The selling price of the first piece is 3 times its cost price, the selling price of the second piece is 3 times the selling price of the first piece, the selling price of the third piece is 3 times the selling price of the second piece and so on. What is his profit percentage on the sale of the first 8 metal pieces?

    Solution

    Let the cost price of each piece be Re 1.
    So, the C.P. of 8 pieces will be Rs 8.
    Then, total selling price of the eight pieces will be = 3 + 32 +33+.....38 = 9840
    Now by formula, Profit % = (9840 - 8)×1008= 122900%

    Hence, the correct option is (d).
  • Question 6
    1 / -0.25

    Two pipes together can fill a tank in 16 hours and one of them alone in 48 hours. How long will the other pipe take to fill the tank alone?

    Solution
    Two pipes together can fill a tank in 16 hours
    =>In one hr =>\(\frac{1}{16}\) full
    One pipe take 48 hours
    =>In one hr =>\(\frac{1}{48}\) full
    The other pipe fills the tank in one hr = \(\frac{1}{16}\)–\(\frac{1}{48}\)=\(\frac{1}{24}\)
    Or the other pipe will fill the whole tank in 24 hrs.
    Hence, the correct option is (a).
  • Question 7
    1 / -0.25

    What is the sum of all the even numbers from 1 to 3,400?

    Solution

    34002 =1,700
    So there are 1,700 even numbers.
    Sum = 1,700(1,700 + 1) = 1,700 × 1,701 = 28,91,700.

    Hence, the correct option is (c).
  • Question 8
    1 / -0.25
    If \(m\) and \(n\) are the roots of the equation \((x+p)(x+q)-k=0,\) then the roots of the equation \((x-m)(x-n)+k=0\) are-
    Solution

    \((x+p)(x+q)-k=0\)

    \(\Longrightarrow x^{2}+(p+q) x+p q-k=0\)

    \(\mathrm{m}\) and \(\mathrm{n}\) are the roots of this equation.

    So, we have 

    Sum of roots \(=-(p+q)=m+n\) 

    Product of the roots \(=p q-k=m n\) 

    \(\Rightarrow p q=m n+k\)

    Consider, \((x-m)(x-n)+k=0\)

    \(\Rightarrow x^{2}-(m+n) x+mn+k=0\)

    Sum of roots is \(m+n\).

    But \(m+n=(-p)+(-q)\)

    Product of the roots \(=m n+k\)

    But \(mn+k=pq=(-p)(-q)\)

    So, the roots of the new equation are \(-p,-q\).

  • Question 9
    1 / -0.25

    For what value of p, will the equation py + 8y = 9 never have a solution?

    Solution

    py + 8y = 9
    => y(p + 8) = 9
    => y = 9(p + 8)
    Here if p = −8 then y will not have a definite value.So answer is −8.

    Hence, the correct option is (d).
  • Question 10
    1 / -0.25

    The area of triangle PRT is how many times the area of the regular hexagon PQRSTU?

    Solution

    In the above diagram, if Triangle PQR, Triangle RST and Triangle PUT are folded inwards (as depicted by dotted lines, they collectively have the same area as Triangle PRT.
    So,
    Area of hexagon PQRSTU = Area of Triangle PRT \(+(\) Sum of areas of Triangle PQR, Triangle RST and Triangle PUT) \(=2 \times\) Area of Triangle PRT
    So,
    Area of Triangle PRT \(=\frac{1}{2}{x}\)
    Area of hexagon PQRSTU.
    Hence, the correct option is (a).
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