Structure of Atom Test

Result

Structure of Atom Test - 5

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Weekly Quiz Competition

Question 1
4 / -1

Most penetrating radiation of radioactive element is:

A
  β — rays

B
  α — rays

C
  x — rays

D
  γ — rays

Solution

Alpha rays as the least penetrating, followed by beta rays, followed by gamma rays as the most penetrating.
Question 2
4 / -1

For a hypothetical H like atom which follows Bohr's model, some spectral lines were observed as shown. If it is known that line 'E' belongs to the visible region, then the lines possibly belonging to ultra violet region will be (n1 is not necessarily ground state)
[Assume for this atom, no spectral series shows overlaps with other series in the emmission spectrum]


A
line B and D

B
line D only

C
line C only

D
line A only

Solution

In the given figure if line 'E' is in visible region then line belonging to ultraviolet region will have more energy than 'E' i.e. line A
Question 3
4 / -1

The number of photons emitted in 10 hours by a 60W sodium lamp (λ, of photon = 6000 Å)
    [Take he = 12400 EvÅ, h = Planck's constant, c = speed of light]

A
6.50 × 10²⁴

B
6.40 × 10²³

C
8.40 × 10²³

D
3.40 × 10²³

Solution
Question 4
4 / -1

Radius of 3rd orbit of Li²⁺ ion is ‘x’ cm then de-broglie wavelength of electrons in the 1^st orbit is

A
cm

B
6πx cm

C
3πx cm

D
cm

Solution
Question 5
4 / -1

Ratio of frequency of revolution of electron in the second state of He^⊕ revolution of electron in the second state He^Θ and second state of hydrogen is

A
32/27, n = 3

B
27/32 , n = 2

C
1/54, n= 1

D
27/2, n = 3

Solution
Question 6
4 / -1

In any subshell, the maximum number of electrons having same value of spin quantum number is:

A

B

C

D

Solution

Maximum number of electron having same spin quantum number is equal to the number of orbitals =
Question 7
4 / -1

A proton accelerated from rest through a potential difference of 'V' volts has a wavelength λ associated with it. An alpha particle in order to have the same wavelength must be accelerated from rest through a potential difference of

A
V volt

B
4V volt

C
2V volt

D
V/8 volt

Solution
Question 8
4 / -1

Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers,  = 1 and 2 are, respectively:

A
    16 and 5

B
    12 and 5

C
    16 and 4

D
    12 and 4

Solution

Sol.   = 1 p and = 2 for d.
Now Cr has configuration
1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹
Hence there are 12, p-electrons and 5, d-electrons
Question 9
4 / -1

Number of electrons having l + m value equal to zero in ₂₆Fe may be

A
13

B
14

C
7

D
12

Solution
Question 10
4 / -1

A photon of 4000 is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I₂ molecule is 246.5 kJ/mol is:

A
8%

B
12%

C
17%

D
25%

Solution

Energy of one photon
Energy supplied by one mole photon in KJ/mole = 3.11×6×10⁻¹⁹×6×10²³×10⁻³=297KJ/mole
% of energy converted to K.E.=