Chemical Kinetics Test

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Chemical Kinetics Test - 18

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Weekly Quiz Competition

Question 1
4 / -1

If E_f and E_r are the activation energies of the forward and reverse reactions and the reaction is known to be exothermic then

A
E_f < E_r

B
E_f > E_r

C
E_f >>> E_r

D
E_f = E_r
Question 2
4 / -1

For a an endothermic reaction, ∆H represents the enthalpy of reaction. The minimum value for the energy of activation will be ...

A
equal to ∆H

B
zero

C
more than ∆H

D
less than ∆H
Question 3
4 / -1

For an endothermic reaction A → B. An activation energy of 15 Kcal mole^-1 and the enthalpy change of reaction is 5 Kcal mole^-1. The activation energy for the reaction B → A is

A
10 Kcal mole^-1

B
20 Kcal mole^-1

C
15 Kcal mole^-1

D
zero
Question 4
4 / -1

The Plot of log K vs 1/T helps to calculate

A
Activation energy

B
Rate constant

C
Reaction order

D
Activation energy and frequency factor
Question 5
4 / -1

The increase in reaction rate as a result of temperature rise from 10 K to 100 K is ...

A
512

B
614

C
400

D
112
Question 6
4 / -1

At 300 K rate constant is 0.0231 min^-1, for a reaction. Bt at 320 K rate constant is 0.0693 min^-1.The activation energy of the reaction is

A
84 KJ mole^-1

B
34.84 KJ mole^-1

C
43.84 KJ mole^-1

D
30 KJ mole^-1

Solution
Question 7
4 / -1

The activation energy of a reaction is 9 Kcal mole^-1. The increase in the rate constant when its temperature is raised from 295 to 300 K is approximately

A
1.289 times

B
12.89 times

C
0.1289 times

D
25%

Solution
Question 8
4 / -1

The rate of reaction 2x + y → Products. Rate = K[x]²[y]. If x is present in large excess, the order of the reaction is

A
3

B
2

C
1

D
0
Question 9
4 / -1

A
0

B
1

C
2

D
3
Question 10
4 / -1

In which of the following cases, does the reaction go farthest to completion ?

A
K = 100

B
K = 10^-2

C
K = 10

D
K = 1

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Chemical Kinetics Test - 18

Result

Chemical Kinetics Test - 18

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Question 1

Ef < Er

Ef > Er

Ef >>> Er

Ef = Er

Question 2

equal to ∆H

zero

more than ∆H

less than ∆H

Question 3

10 Kcal mole-1

20 Kcal mole-1

15 Kcal mole-1

zero

Question 4

Activation energy

Rate constant

Reaction order

Activation energy and frequency factor

Question 5

512

614

400

112

Question 6

84 KJ mole-1

34.84 KJ mole-1

43.84 KJ mole-1

30 KJ mole-1

Solution

Question 7

1.289 times

12.89 times

0.1289 times

25%

Solution

Question 8

3

2

1

0

Question 9

0

1

2

3

Question 10

K = 100

K = 10-2

K = 10

K = 1

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E_f < E_r

E_f > E_r

E_f >>> E_r

E_f = E_r

10 Kcal mole^-1

20 Kcal mole^-1

15 Kcal mole^-1

84 KJ mole^-1

34.84 KJ mole^-1

43.84 KJ mole^-1

30 KJ mole^-1

K = 10^-2