Chemical Kinetics Test

Result

Chemical Kinetics Test - 23

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Weekly Quiz Competition

Question 1
4 / -1

A reaction involving A, B and C as reactants is found to obey the rate law, rate = k [A]^x [B]^y [C]^z . When the concentrations of A, B and C are doubled separately, the rate is also found to increase two, zero and four times respectively. The overall order of the reaction is

A
1

B
2

C
3

D
4

Solution
Question 2
4 / -1

For the reaction system,
2NO(g ) +O₂(g)→ 2NO ₂(g)
volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order with respect to O₂ and second order with respect to NO; the rate of reaction will

A
diminish to one-fourth of its initial value

B
diminish to one-eighth of its initial value

C
increase to eight times of its initial value

D
increase to four times of its initial value

Solution
Question 3
4 / -1

The rate equation for the reaction 2A + B → C is found to be rate = k [A] [B] The correct statement in relation to this reaction is that the

A
unit of k must be s ^-1

B
t_1/2 is a constant

C
rate of formation of C is twice the rate of disappearance of A

D
value of k is independent of the initial concentrations of A and B

Solution
Question 4
4 / -1

A
mol^-1 L s^-1

B
s^-1

C
s

D
s^-1 mol L ^-1

Solution
Question 5
4 / -1

Which one of the following is wrongly matched ?

A
Saponification of CH₃COOC₂H₅ — second order reaction

B
Hydrolysis of CH₃COOCH₃ — pseudo unimolecular reaction

C
Decomposition of H₂O₂ — first order reaction

D
Combination of H₂ and Br₂ to give HBr — first order reaction

Solution
Question 6
4 / -1

The decomposition of N₂ O₅ occurs as 2N₂ O₅ → 4NO₂ + O₂, and follows 1st order kinetics, hence

A
the reaction is unimolecular

B
the reaction is bimolecular

C
t_1/2 ∝ a⁰

D
None of the above

Solution
Question 7
4 / -1

In the reaction, 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate constant k is 3.38 × 10^-5 s ^-1. After 10 min the final pressure of N₂O₅ is

A
490 atm

B
250 atm

C
480 atm

D
420 atm

Solution
Question 8
4 / -1

Mathematical expression for t_1/4 i.e. when (1/4)^th reaction is over following first order kinetics can be given by

A

B

C

D

Solution
Question 9
4 / -1

A plot of 1/ T versus k for a reaction gives the slope -1 × 10⁴ K. The energy of activation for the reaction is (Given, R = 8.314 K^-1 mol^-1 )

A
83.14 J mol^-1

B
1.202 kJ mol^-1

C
12.02 J mol^-1

D
83.14 kJ mol^-1

Solution
Question 10
4 / -1

The rate of reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be (R = 8.314 JK^-1 mo1^-1 and log 2 = 0.301)

A
53.6 kJ mo1^-1

B
48.6 kJ mo1^-1

C
58.5 kJ mo1^-1

D
60.5 kJ mo1^-1

Solution