D and F Block Elements Test

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D and F Block Elements Test - 8

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Weekly Quiz Competition

Question 1
1 / -0

Chromyl chloride test can be used to confirm the presence of Cl^- ion in the compound

A
HgCl₂

B
PbCI₂

C
BaCI₂

D
AgCI

Solution

Other chlorides are not volatile enough to form CrO₂CI₂.

The correct answer is: BaCI₂
Question 2
1 / -0

The transition metals have comparatively less tendency to form cations as compared to elements of I, II and III A (13th) groups. This is because of

A
all

B
high heats of sublimation

C
low heats of hydration of their ions

D
their high energies of ionization

Solution

High energies of ionization and low heats of hydration of their ions and high heats of sublimation are the reason behind less tendency to form cations as compared to elements of I, II and III A groups.

The correct answer is: all
Question 3
1 / -0

Which of the following compounds is not the substance of primary standard?

A
K₂Cr₂O₇

B
CuSO₄.5H₂O

C
FeSO₄.7H₂O

D
(NH₄ )₂ SO₄ . FeSO₄ . 6H₂O

Solution

FeSO₄ 7H₂O is oxidised by oxygen of air and hence its composition changes with time.
4FeSO₄ + 2H₂O + O₂→ 4 Fe (OH)SO₄

The correct answer is: FeSO₄.7H₂O
Question 4
1 / -0

In the Mac-Arther Cyanide process for extraction of silver, a small amount of KNO₃ is added. The function of KNO₃ is

A
to form anions with Ag+ which is then reduced to metallic silver by zinc

B
to oxidise Ag in natural form to Ag+

C
to oxidise the sulphur present in argentite ore to SO2

D
to oxidise the impurities of lead and zinc present in it

Solution

KNO₃ is added to oxidise the lead and zinc impurities.

The correct answer is: to oxidise the impurities of lead and zinc present in it
Question 5
1 / -0

In the reduction of Au (III) from AuCl₄^- ion, the solution is to be stirred rapidly during electrolysis. The stirring is quite important

A
for separation of gold from chlorine

B
for overcoming the repulsive forces between the AuCl₄^- and excess electrons at the electrode so as to help the deposition of Au (III)

C
for increasing the movement of AuCl₄^- ions towards the anode

D
for increasing the conductivity of the solution

Solution

Stirring is needed for reduction of Au (III) in AuCI₄^- at the electrode.

The correct answer is: for overcoming the repulsive forces between the AuCl₄^- and excess electrons at the electrode so as to help the deposition of Au (III)
Question 6
1 / -0

The reason for the existence of mercury metal in liquid state at 0°C is that

A
mercury has a very high atomic weight

B
mercury has low ionisation energy

C
mercury has high ionisation energy and posseses weak metallic bond

D
mercury has a high vapour pressure

Solution

The reason for existence of mercury metal in liquid state even at 0°C is its very high ionisation energy and presence of weak metallic bond because of absence of unpaired electrons.

The correct answer is: mercury has high ionisation energy and posseses weak metallic bond
Question 7
1 / -0

The Guigret's green can be represented as

A
CrO.2H₂O

C
FeSO₄.7H₂O

D
Cr₂O₃.2H₂O

E
CuSO₄.2H₂O

Solution

Cr₂O₃.2H₂O is known as Guigret's green.

The correct answer is: Cr₂O₃.2H₂O
Question 8
1 / -0

Statement-1 : The orange colour of K₂Cr₂O₇ is due to polarisation.

Statement-2 : In Cr₂O₇^2- ion all bonds between Cr and oxygen are not identical.

A
Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

B
Statement-1 is true but Statement-2 is false.

C
Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

D
Statement-1 is false but Statement-2 is true.

Solution

Assertion is wrong. Reason is correct. The orange colour of K₂Cr₂O₇ is due to Cr₂O₇^2- ions.

The correct answer is: Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.
Question 9
1 / -0

Identify the correct statements of the following

A
The atomic sizes of third series of transition metals are not very much different from those of second series in respective groups

B
Transition metals have high enthalpies of sublimation

C
Cr, Mo and W are very hard metals because of greater number of covalent bonds involving unpaired electrons.

D
Most of the transition metals of first series have negative reduction potentials and hence react readily with dilute acids to liberate H₂

Solution

Given all statements are correct.

The correct answer is: Transition metals have high enthalpies of sublimation, The atomic sizes of third series of transition metals are not very much different from those of second series in respective groups, Most of the transition metals of first series have negative reduction potentials and hence react readily with dilute acids to liberate H₂, Cr, Mo and W are very hard metals because of greater number of covalent bonds involving unpaired electrons.

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D and F Block Elements Test - 8

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D and F Block Elements Test - 8

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Question 1

HgCl2

PbCI2

BaCI2

AgCI

Solution

Question 2

all

high heats of sublimation

low heats of hydration of their ions

their high energies of ionization

Solution

Question 3

K2Cr2O7

CuSO4.5H2O

FeSO4.7H2O

(NH4 )2 SO4 . FeSO4 . 6H2O

Solution

Question 4

to form anions with Ag+ which is then reduced to metallic silver by zinc

to oxidise Ag in natural form to Ag+

to oxidise the sulphur present in argentite ore to SO2

to oxidise the impurities of lead and zinc present in it

Solution

Question 5

for separation of gold from chlorine

for overcoming the repulsive forces between the AuCl4- and excess electrons at the electrode so as to help the deposition of Au (III)

for increasing the movement of AuCl4- ions towards the anode

for increasing the conductivity of the solution

Solution

Question 6

mercury has a very high atomic weight

mercury has low ionisation energy

mercury has high ionisation energy and posseses weak metallic bond

mercury has a high vapour pressure

Solution

Question 7

CrO.2H2O

FeSO4.7H2O

Cr2O3.2H2O

CuSO4.2H2O

Solution

Question 8

Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

Statement-1 is true but Statement-2 is false.

Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

Statement-1 is false but Statement-2 is true.

Solution

Question 9

The atomic sizes of third series of transition metals are not very much different from those of second series in respective groups

Transition metals have high enthalpies of sublimation

Cr, Mo and W are very hard metals because of greater number of covalent bonds involving unpaired electrons.

Most of the transition metals of first series have negative reduction potentials and hence react readily with dilute acids to liberate H2

Solution

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HgCl₂

PbCI₂

BaCI₂

K₂Cr₂O₇

CuSO₄.5H₂O

FeSO₄.7H₂O

(NH₄ )₂ SO₄ . FeSO₄ . 6H₂O

for overcoming the repulsive forces between the AuCl₄^- and excess electrons at the electrode so as to help the deposition of Au (III)

for increasing the movement of AuCl₄^- ions towards the anode

CrO.2H₂O

FeSO₄.7H₂O

Cr₂O₃.2H₂O

CuSO₄.2H₂O

Most of the transition metals of first series have negative reduction potentials and hence react readily with dilute acids to liberate H₂