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Coordination Compounds Test - 2

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Coordination Compounds Test - 2
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Weekly Quiz Competition
  • Question 1
    1 / -0

    How many number of isomers of the complex [MCl2Br2]SO4 is possible?

    Solution

    4 isomers of complex [MCl2Br2]SO4 is possible.

    The correct answer is: 4

     

  • Question 2
    1 / -0

    Statement-1:H2N-NH2 is a chelating ligand.

    Statement-2: A chelating ligand must possess two ormore lone pairs at such a distance that itmay form suitable strain free rings at themetal ion.

    Solution

    H2N NH2 does not act as chelating ligand. The coordination by hydrazine leads to a three member highly unstable strained ring and thus it does not act as chelating agent.

    The correct answer is: Statement-1 is false but Statement-2 is true.

  • Question 3
    1 / -0

    The IUPAC name of the red coloured complex [Fe(C4H7O2N2)2] obtained from the reaction of Fe2+ and dimethyl glyoxime

    Solution

    The IUPAC name [Fe(C4H7O2N2)2] is

    bis (2,3- butanedione dioximato) iron (II).

    The correct answer is: bis (2,3- butanedione dioximato) iron (II)

  • Question 4
    1 / -0

    Statement-1: [Ni(CO)4] has square planar geometry while [Ni(CN)4]4- has tetrahedral geometry.

    Statement-2: Geometry of any complex depends upon the nature of ligands attached.

    Solution

    Ni(CO)4 has tetrahedral geometry and [Ni(CN)4]4– has square planer geometry. [Ni(CO)4] possesses sp3 hybridization whereas [Ni(CN)4– has dsp2 hybridization to show square planer geometry.

    The correct answer is: Statement-1 is false but Statement-2 is true.

     

  • Question 5
    1 / -0

    Coordination isomerism could not be shown by

    Solution

    [Ag(NH3)2][CuCl2] and [Co(NH3)5Cl]SO4 could not show coordination isomerism.

    The correct answer is: [Ag(NH3)2][CuCl2], [Co(NH3)5Cl]SO4

  • Question 6
    1 / -0

    In which of the following complexes there are d5configurations?

    Solution

    Fe(III) : 3d1; d2sp3 (paired spin complex, CN- being a strong ligand)

    Fe(II) : 3d0; d2sp3 (paired spin complex)

    Fe(III) : 3d5; sp3d2 (free spin complex, H2O being a weak ligand)

    Mn(II) : 3d5; sp3 (free spin complex, Cl- being a weak ligand)

    The correct answer is: [Fe(H2O)6]3+, [MnCI4]2–

     

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