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Coordination Compounds Test - 3

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Coordination Compounds Test - 3
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  • Question 1
    1 / -0

    Choose the correct name for the formula [Co(en)2(NH3)2]Cl3

    Solution

    The correct IUPAC name of the compound [Co(en)2(NH3)2]Cl3 is Diammine Bis(ethylenediammine)cobalt(III) chloride.

     

  • Question 2
    1 / -0

    What is the correct IUPAC name of Na3[FeCl(CN)5]?

    Solution

    The correct IUPAC name of Na3[FeCl(CN)5] is Sodium monochloropentacyanoferrate(III).

     

  • Question 3
    1 / -0

    Which of the following 'Formula : Name' combinations is incorrect?

    Solution

    Correct IUPAC name of [Cr(NH3)4(OH)2]Br is tetraamminedihydroxochromium(III) bromide.

     

  • Question 4
    1 / -0

    Which of the following is/are outer orbital complex(es)?

    Solution

    [FeF6]3–

    The d-electron configuration of Fe3+ is d5

    The splitting energy of F- ions is small. Inner d-orbitals will take part in hybridisation (sp3d2hybridisation).

    Therefore, the complex [FeF6]3– is outer orbital complex.

    The complex has an octahedral shape.

    [Co(NH3)6]3+

    NH3 is a strong-field ligand.

    The d-electron configuration of Co3+ is d6.

    The splitting energy is large. Inner d-orbitals will take part in hybridisation (d2sp3 hybridisation).

    Therefore, the complex [Co(NH3)6]3+ is inner orbital complex. The complex has an octahedral shape.

    [Fe(CN)6]3-

    CN- is a strong-field ligand.

    The d-electron configuration of Fe3+ is d5.

    The splitting energy is large. Inner d-orbitals will take part in hybridisation (d2sp3 hybridisation).

    Therefore, the complex [Fe(CN)6]3- is inner orbital complex.

     

  • Question 5
    1 / -0

    Which of the following complexes has square planar geometry?

    Solution

    With a second row d8 metal ion such as Pd2+ (which already generates a strong field), even a weak field ligand Cl-leads the formation of a square planar complex. Example: PdCl42-

    MnO4- has tetrahedral geometry.

    FeCl4- has tetrahedral geometry.

    CoCl42- has tetrahedral geometry.

     

  • Question 6
    1 / -0

    Which of the following is/are inner orbital complex(es)?

    1. [Cr(NH3)6]3+ 

    2. [Fe(CN)6]4- 

    3. [Fe(H2O)6]2+

    Solution

    As both NH3 and CN- are strong field ligands, so energy splitting is high. Therefore, in [Cr(NH3)6]3+ and [Fe(CN)6]4-, inner d-orbitals take part in hybridisation (d2sp3). Thus, both form inner orbital complexes.

     

  • Question 7
    1 / -0

    Which of the following is a pair of linkage isomers?

    Solution

    Option (4) is a pair of linkage isomers.

    In [Co(ONO)(NH3)5]Cl, the NO2- ligand bonds through the oxygen end; and in [Co(NO2)(NH3)5]Cl, the NO2- ligand bonds through the nitrogen end.

    Option (1) is a pair of coordination isomers.

    Option (2) is a pair of ionisation isomers.

    Option (3) is a pair of hydrate isomers.

     

  • Question 8
    1 / -0

    The coordination compound used in the chemotherapy of cancer is

    Solution

    cis-[Pt(NH3)2Cl2] commonly called cis platin is used as an anti-cancerous drug. 

     

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