Chemical Bonding Test

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Chemical Bonding Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following hydrogen bonds is the strongest?

A
O — H …. O

B
O — H …… F

C
O — H ….. N

D
F — H ....... F

Solution

Higher the electronegative difference between the two atoms, stronger will be the bond formed between them. Among the given compounds, electronegative difference between the hydrogen and fluorine is the maximum. Hence, the hydrogen bond in HF is the strongest.
Question 2
1 / -0

The decreasing values of bond angles from NH₃ (106 °) to SbH₃ (101 °) down group-15 of the periodic table is due to

A
decreasing 1p – bp repulsion

B
increasing electronegativity

C
increasing bp – bp repulsion

D
increasing p-orbital character in sp³

Solution

The bond angle decreases from tetrahedral angle of 109 °28′ to 107 ° in NH₃ because lp – bp repulsion. On moving form NH₃ to SbH₃, the electronegativity of the central atom decreases, so, bp – bp repulsion decreases and hence bond angle decreases.

Decrease in bond angle is also caused due to increase in p-character of the hybrid (sp³) orbital. In SbH₃ the bond angle decreases to almost 101 ° indicating that pure p-orbitals are involved in bonding.
Question 3
1 / -0

The bond order in NO is 2.5 while that in NO⁺ is 3. Which of the following statements is true for these two species?

A
Bond length in NO⁺ is greater than in NO

B
Bond length is unpredictable

C
Bond length in NO⁺ in equal to that in NO

D
Bond length in NO is greater than in NO⁺

Solution

Bond order of NO = 2.5
Bond order of NO⁺ = 3
Higher the bond order shorter is the bond length
Question 4
1 / -0

The correct order of bond angles (smallest first) in H₂S, NH₃, BF₃ and SiH₄ is

A
H₂S < SiH₄< NH₃< BF₃

B
H₂S < NH₃< BF₃< SiH₄

C
H₂S < NH₃< SiH₄< BF₃

D
NH₃< H₂S < SiH₄< BF₃

Solution

H₂S → sp³ with 2 lone pairs
NH₃→ sp³ with 1 lone pair
BF₃→ sp² no lone pair, trigonal planar
SiH₄→ sp³no lone pair, tetrahedral
Question 5
1 / -0

Among the following the maximum covalent character is shown by the compound

A
FeCl₂

B
SnCl₂

C
AlCl₃

D
MgCl₂

Solution

Higher the positive oxidation state higher will be the covalent character.
Hence, option C is correct.

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Chemical Bonding Test - 3

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Chemical Bonding Test - 3

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Question 1

O — H …. O

O — H …… F

O — H ….. N

F — H ....... F

Solution

Question 2

decreasing 1p – bp repulsion

increasing electronegativity

increasing bp – bp repulsion

increasing p-orbital character in sp3

Solution

Question 3

Bond length in NO+ is greater than in NO

Bond length is unpredictable

Bond length in NO+ in equal to that in NO

Bond length in NO is greater than in NO+

Solution

Question 4

H2S < SiH4< NH3< BF3

H2S < NH3< BF3< SiH4

H2S < NH3< SiH4< BF3

NH3< H2S < SiH4< BF3

Solution

Question 5

FeCl2

SnCl2

AlCl3

MgCl2

Solution

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increasing p-orbital character in sp³

Bond length in NO⁺ is greater than in NO

Bond length in NO⁺ in equal to that in NO

Bond length in NO is greater than in NO⁺

H₂S < SiH₄< NH₃< BF₃

H₂S < NH₃< BF₃< SiH₄

H₂S < NH₃< SiH₄< BF₃

NH₃< H₂S < SiH₄< BF₃

FeCl₂

SnCl₂

AlCl₃

MgCl₂