Chemical Bonding Test

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Chemical Bonding Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Select the correct statement from the following?

A
Covalent hydrides are formed by s-block elements.

B
The stability of covalent hydrides decreases in a period from left to right

C
Co-valent hydrides have low melting and boiling points

D
Co-valent compounds are good conductor of electricity.

Solution

Covalent hydrides are formed by p-block elements with general formula MH_{18 – a} where ‘a’ is the group to which M belongs and the stability of covalent hybrids increases in a period from left to right with increase in electronegativity.
Question 2
1 / -0

Which one of the following groupings represents a collection of isoelectronic species?
(At. Numbes : Cs-55, Br-35)

A
Na⁺, Ca²⁺, Mg²⁺

B
N^3–, F^–, Na⁺

C
Be, Al³⁺, Cl^–

D
Ca²⁺, Cs⁺, Br

Solution

N^3– 7 + 3 = 10 electrons
F^– 9 + 1 = 10 electrons
Na⁺ 11 – 1 = 10 electrons
Hence, option B is correct.
Question 3
1 / -0

Lattice energy of an ionic compounds depends upon

A
Charge on the ion only

B
Size of the ion only

C
Packing of ions only

D
Charge on the ion and size of the ion

Solution

Lattice energy of an ionic compounds depends upon Charge on the ion and size of the ion.
Hence, option D is correct.
Question 4
1 / -0

Match the items under list (1) with items under list (2) select the correct answers from the sets (A), (B), (C) and (D)-
List (1) molecule
A. PCl₅
B. F₂O
C. BCl₃
D. NH₃

List (2) shape
(i) V-shaped

(ii) Trigonal planar

(iii) Trigonal bipyramidal

(iv) Trigonal pyramidal

(v) Tetrahedral

A
a - i, b - v, c - iv, d - iii

B
a -ii, b -iii, c - i, d - ii

C
a - iv, b - iii, c - ii, d - v

D
a - iii, b - i, c - ii, d - iv

Solution

PCl₅ = sp³d, no LP. Trigonal bipyramidal
F₂O = sp³, 2 LP., V-shape
BCl₃ = sp², no LP., Trigonalplanar
NH₃ = sp³, LP. , Trigonal Pyramidal
Question 5
1 / -0

The pair of species with similar shape is

A
PCl₃, NH₃

B
CF_4, SF₄

C
PbCl₂, CO₂

D
PF₅, IF₅

Solution

Both have pyramidal structure.

CF₄ is tetrahedral, while SF₄ is sea-saw

CO₂ is linear while PbCl₂ is v-shaped

PF₅ is trigonal bipyramidal and IF₅ is square pyramidal

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Chemical Bonding Test - 4

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Chemical Bonding Test - 4

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Question 1

Covalent hydrides are formed by s-block elements.

The stability of covalent hydrides decreases in a period from left to right

Co-valent hydrides have low melting and boiling points

Co-valent compounds are good conductor of electricity.

Solution

Question 2

Na+, Ca2+, Mg2+

N3–, F–, Na+

Be, Al3+, Cl–

Ca2+, Cs+, Br

Solution

Question 3

Charge on the ion only

Size of the ion only

Packing of ions only

Charge on the ion and size of the ion

Solution

Question 4

a - i, b - v, c - iv, d - iii

a -ii, b -iii, c - i, d - ii

a - iv, b - iii, c - ii, d - v

a - iii, b - i, c - ii, d - iv

Solution

Question 5

PCl3, NH3

CF4, SF4

PbCl2, CO2

PF5, IF5

Solution

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Na⁺, Ca²⁺, Mg²⁺

N^3–, F^–, Na⁺

Be, Al³⁺, Cl^–

Ca²⁺, Cs⁺, Br

PCl₃, NH₃

CF_4, SF₄

PbCl₂, CO₂

PF₅, IF₅