Analytical Chemistry Test

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Analytical Chemistry Test - 7

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Weekly Quiz Competition

Question 1
4 / -1

200 ml 0.6 N H₂SO₄ and 100 ml of 0.3N HCl are mixed together. Acidic normality of the resultant solution is:

A
0.5 N

B
0.9 N

C
0.3 N

D
0.6 N

Solution

N₁V₁ + N₂V₂ = N₃V₃

= 300 ml

∴ N₃ = 0.5 N
Question 2
4 / -1

A mixture containing Cd²⁺ and Ni²⁺ can be separated for identification by:

A
Passing H²S in acid medium

B
Passing H₂S in alkaline medium

C
Passing H₂S in neutral medium

D
Passing H₂S in dry mixture

Solution

Cu²⁺ will be precipitated as CuS in acidic medium where as Ni²⁺ is not precipitated.
Question 3
4 / -1

Which one of the following sulphides is only completely precipitated when the acidic solution is made dilute?

A
HgS

B
PbS

C
CdS

D
CuS

Solution

Sulphide having high ionic product are completely precipitated in acidic medium. CdS has maximum ionic product hence it is completely precipitated.
Question 4
4 / -1

25 ml of a solution of Na₂CO₃ having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5grams of the acid per litre for complete neutralization. Calculate the volume of 0.84 N – H₂SO₄ that will be completely neutralized by 125 grams of the Na₂CO₃ solution:

A
460 ml

B
540 ml

C
480 ml

D
470 ml

Solution

N₁ V₁ = N₂ V₂
Question 5
4 / -1

In order to prepare one litre normal solution of KMnO₄, how many gm of KMnO₄ are required, if the solution is to be used in acid medium for oxidation:

A
158 gm

B
31.60 gm

C
62.0 gm

D
790 gm

Solution

In acidic medium 2 molecules of KMnO₄ gives 5 atoms of oxygen
Question 6
4 / -1

How many grams of NaOH are equivalent to 100 ml of 0.1 N oxalic acid?

A
0.2

B
2.0

C
0.4

D
4.0

Solution
Question 7
4 / -1

0.126g of an acid requires 20 ml of 0.1N NaOH for complete neutralization. The equivalent weight of the acid is:

A
45

B
53

C
40

D
63

Solution

20 ml of 0.1N NaOH neutralize 20 ml of 0.1N acid Weight of acid = 0.216 g
Question 8
4 / -1

0.16 gm of a dibasic acid required 25 ml of decinormal NaOH solution for complete neutralization. The molecular weight of the acid is:

A
32

B
64

C
128

D
256

Solution
Question 9
4 / -1

0.1914g of an organic acid is dissolved in approx. 20 ml of water. 25 ml of 0.12 N NaOH required for the complete neutralization of the acid solution. The equivalent weight of the acid is:

A
65

B
64

C
63.80

D
62.50

Solution
Question 10
4 / -1

1 gm of hydrogen is found to combine with 80 gms of bromine. 1 gm of calcium (valency 2) combines with 4 gms of bromine. The equivalent weight of calcium is:

A
10

B
20

C
40

D
80

Solution

4 gms of Br₂ combines with 1 gm of Ca

∴ 80 gms of Br combines with 1/4 × 80 = 20

Therefore, equivalent wt of Ca = 20