Classification of Elements Test

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Classification of Elements Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

In which of the following arrangements the order is NOT according to the property indicated against it?

A
Al³⁺ < Mg²⁺ < Na⁺ < F^- Increasing ionic size

B
B < C < N < O Increasing first ionization enthalpy

C
I < Br < F < CI Increasing electron gain enthalpy (with negative sign)

D
Li < Na < K < Rb Increasing metallic radius

Solution

B < C < O < N

Hence, option B is correct.
Question 2
1 / -0

Which one of the following orders presents the correct sequence of the increasing basic nature of the given oxides?

A
Al₂O₃ < MgO < Na₂O < K₂O

B
MgO < K₂O < Al₂O₃ < Na₂O

C
Na₂O < K₂O < MgO < Al₂O₃

D
K₂O < Na₂O < Al₂O₃ < MgO

Solution

Metallic property increases down the group and decreases across a period when moved from left to right.
Hence, option A is correct.
Question 3
1 / -0

Among Al₂O₃, SiO₂, P₂O₃ and SO₂ the correct order of acid strength is

A
SO₂< P₂O₃< SiO₂< Al₂O₃

B
Al₂O₃< SiO₂< P₂O₃< SO₂

C
Al₂O₃< SiO₂< SO₂< P₂O₃

D
SiO₂< SO₂< Al₂O₃< P₂O₃

Solution

While moving along a group from top to bottom, acidic nature of oxides decreases and along a period left to right, acidic nature increases.
Al, Si, P, S acidity of oxides increases
Question 4
1 / -0

Which of the following has largest radius?

A
Mg²⁺

B
Na⁺

C
O^2–

D
F^¯

Solution

In iso electronic species as effective nuclear charge decrease size increase.
Question 5
1 / -0

Which of the following elements has highest value of I.P.?

A
Ti

B
Zr

C
Hf

D
Cs

Solution

Due to increase (+32) effective nuclear charge Hf has highest value of I.P.
Question 6
1 / -0

The atomic numbers of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second inonization enthalpy?

A
V

B
Cr

C
Mn

D
Fe

Solution

Electronic configuration of V= [Ar]3d³4s²

Electronic configuration of Cr= [Ar]3d⁵4s¹

Electronic configuration of Mn= [Ar]3d⁵4s²

Electronic configuration of Fe= [Ar]3d⁶4s²

From the given electronic configurations, it can be easily seen that after losing one electron, chromium will attain the half-filled electronic configuration which is quite stable. Hence, it will be difficult to remove second electron from the d-orbital. Thus, chromium will have the highest second ionization enthalpy among the given elements.
Question 7
1 / -0

Which is not the correct order of electronegativity?

A
Cl > S > P > Si

B
Si > Al > Mg > Na

C
F > Cl > Br > I

D
None of these

Solution

All have correct order of E.N.

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Classification of Elements Test - 3

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Classification of Elements Test - 3

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Question 1

Al3+ < Mg2+ < Na+ < F- Increasing ionic size

B < C < N < O Increasing first ionization enthalpy

I < Br < F < CI Increasing electron gain enthalpy (with negative sign)

Li < Na < K < Rb Increasing metallic radius

Solution

Question 2

Al2O3 < MgO < Na2O < K2O

MgO < K2O < Al2O3 < Na2O

Na2O < K2O < MgO < Al2O3

K2O < Na2O < Al2O3 < MgO

Solution

Question 3

SO2< P2O3< SiO2< Al2O3

Al2O3< SiO2< P2O3< SO2

Al2O3< SiO2< SO2< P2O3

SiO2< SO2< Al2O3< P2O3

Solution

Question 4

Mg2+

Na+

O2–

F ¯

Solution

Question 5

Ti

Zr

Hf

Cs

Solution

Question 6

V

Cr

Mn

Fe

Solution

Question 7

Cl > S > P > Si

Si > Al > Mg > Na

F > Cl > Br > I

None of these

Solution

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Al³⁺ < Mg²⁺ < Na⁺ < F^- Increasing ionic size

Al₂O₃ < MgO < Na₂O < K₂O

MgO < K₂O < Al₂O₃ < Na₂O

Na₂O < K₂O < MgO < Al₂O₃

K₂O < Na₂O < Al₂O₃ < MgO

SO₂< P₂O₃< SiO₂< Al₂O₃

Al₂O₃< SiO₂< P₂O₃< SO₂

Al₂O₃< SiO₂< SO₂< P₂O₃

SiO₂< SO₂< Al₂O₃< P₂O₃

Mg²⁺

Na⁺

O^2–

F^¯