Some Basic Concepts of Chemistry Test

Result

Some Basic Concepts of Chemistry Test - 7

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Weekly Quiz Competition

Question 1
4 / -1

Boron has two stable isotopes, ¹⁰B(19%) and ¹¹B(81%). The atomic mass that should appear for boron in the periodic table is

A
10.8

B
10.2

C
11.2

D
10.0

Solution
Question 2
4 / -1

The molecular weight of O₂ and SO₂ are 32 and 64 respectively. At 15^o C and 150 mm Hg pressure, one litre of O₂ contains ‘N’ molecules. The number of molecules in two litres of SO₂ under the same conditions of temperature and pressure will be :

A
N/2

B
N

C
2N

D
4N
Question 3
4 / -1

A
41.59 g

B
415.9 g

C
4.159 g

D
none of the three

Solution
Question 4
4 / -1

The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with ZnSO₄. 7H₂O. The atomic weight of M is

A
40.3

B
36.3

C
24.3

D
11.3

Solution
Question 5
4 / -1

A 5 molar solution of H₂SO₄is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be :

A
1N

B
0.1N

C
5N

D
0.5N
Question 6
4 / -1

1.25g of a solid disbasic acid is completely neutralised by 25 mL of 0.25 molar Ba(OH)₂ solution. Molecular mass of the acid is

A
100

B
150

C
120

D
200

Solution
Question 7
4 / -1

The law of multiple proportions was proposed by

A
Lavoisier

B
Dalton

C
Proust

D
Gay- Lussac
Question 8
4 / -1

0.115 g of pure sodium metal was dissolved in 500 mL distilled water. The normality of the solution would be [ Na = 23 ]

A
0.010 N

B
0.00115 N

C
0.023 N

D
0.046 N

Solution
Question 9
4 / -1

How many millilitres (mL) of 1 M H₂SO₄ solution is required to neutralise 10 mL of 1 M NaOH solution ?

A
2.5 mL

B
5.0 mL

C
10.0 mL

D
20.0 mL

Solution
Question 10
4 / -1

Rearrange the following (I to IV ) in the order of increasing masses and choose the correct answer from (a), (b) ,(c) and (d) ( Atomic mass :N =14, O=16, Cu =63).
I. 1 molecule of oxygen
II. 1 atom of nitrogen
III. 1 × 10^-10 g molecular weight of oxygen
IV. 1 × 10^-10 g atomic weight of copper

A
II < I < III < IV

B
IV < III < II < I

C
II < III < I < IV

D
III < IV < I < II

Solution