Gaseous State Test

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Gaseous State Test - 15

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Weekly Quiz Competition

Question 1
4 / -1

A perfect gas at 27°C is heated at constant pressure to 327°C. If original volume of gas at 27°C is V then volume at 327°C is:

A
V

B
3V

C
2V

D
V/2

Solution

From Charle’s law V α T
Question 2
4 / -1

A gas is filled in the cylinder shown in the figure. The two pistons are joined by a string. If the gas is heated, the pistons will:

A
Move towards left

B
Move towards right

C
Remain stationary

D
None of these

Solution

When temperature of gas increases it expands. As the cross-sectional area of right piston is more, therefore greater force will work on it (because F = PA). So piston will move towards right.
Question 3
4 / -1

The capacity of a vessel is 3 litres. It contains 6 gm oxygen, 8 gm nitrogen and 5 gm CO₂ mixture at 27°C. If R = 8.31 J/mole × kelvin, then the pressure in the vessel in N/m²will be: (approx.)

A
5 × 10⁵

B
5 × 10⁴

C
10⁶

D
10⁵

Solution

Dalton’s law
Question 4
4 / -1

A closed vessel contains 8g of oxygen and 7g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent the pressure of the remaining gas in atm will be:

A
2

B
10

C
4

D
5

Solution

From Dalton’s law final pressure of the mixture of nitrogen and oxygen

From equation (i) and (ii) we get pressure of the nitrogen P = 5 atm.
Question 5
4 / -1

Temperature of an ideal gas is T K and average kinetic energy is E = 2.07× 10^-23 T Joule/molecule. Number of molecules in 1 litre gas at S.T.P. will be:

A
2.68 × 10²²

B
2.68 × 10²⁵

C
2.68 × 10²⁸

D
1.68 × 10²²

Solution

As we know that at S.T.P. 22.4 litre of gas contains 6.023 × 10²³ molecules
Question 6
4 / -1

The average kinetic energy per molecule of helium gas at temperature T is E and the molar gas constant is R, then Avogadro’s number is:

A
RT/2E

B
3RT/E

C
E/2RT

D
3RT/2E

Solution

Average kinetic energy per unit molecule E = 3/2 kT

∴ k = 2E/3T
Question 7
4 / -1

Under which of the following conditions is the law PV = RT obeyed most closely by a real gas?

A
High pressure and high temperature

B
Low pressure and low temperature

C
Low pressure and high temperature

D
High pressure and low temperature

Solution

At low pressure and high temperature real gas obey PV = RT i.e. they behave as ideal gas because at high temperature we can assume that there is no force of attraction or repulsion works among the molecules and the volume occupied by the molecules is negligible in comparison to the volume occupied by the gas.
Question 8
4 / -1

The equation of state of a gas is given by = + (RT b), where a, b, c and R are constants. The isotherms can be represented by P = AV^m - BV^m - BVⁿ, where A and B depend only on temperature then?

A
m = −c and n = −1

B
m = c and n = 1

C
m = −c and n = 1

D
m = c and n = –1

Solution

By comparing this equation with given equation
Question 9
4 / -1

Energy of all molecules of a monoatomic gas having a volume V and pressure P is 3/2 PV. The total translational kinetic energy of all molecules of a diatomic gas as the same volume and pressure is:

A
1/2 PV

B
3/2 PV

C
5/2 PV

D
3 PV

Solution

Where f = Degree of freedom Mono-atomic or diatomic both gases posses equal degree of freedom for translational motion and that is equal to 3

Although total energy will be different, For mono-atomic
Question 10
4 / -1

At standard temperature and pressure the density of a gas is 1.3 gm/ m³ and the speed of the sound in gas is 330 m/sec. Then the degree of freedom of the gas will be:

A
3

B
4

C
5

D
6

Solution