Chemical Equilibrium Test

Result

Chemical Equilibrium Test - 10

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

Which of the following is a wrong statement about equilibrium state?

A
Rate of forward reaction =Rate of backward reaction

B
Equilibrium is dynamic

C
Catalysts increase the value of equilibrium constant

D
Free energy change is zero
Question 2
4 / -1

A + B ⇌ C + D
In the above reaction, initially moles of A and B are equal. At equilibrium, moles of C are three times that of A. The equilibrium constant of the reaction will be

A
1

B
3

C
4

D
9
Question 3
4 / -1

If for N₂ + 3H₂ ⇌ 2NH₃, k_eq = 1.6 × 10^-5, then the value of k_eq for the reaction NH₃ ⇌ 1/2 N₂ + 3/2 H₂ will be

A
6.25

B
25

C
250

D
500

Solution
Question 4
4 / -1

3 moles of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction.
3A (g) + 4B (g) ⇌ 2C (g) + 3D (g)
When equilibrium is reached, there is 1 mole of C. The equilibrium extent of the reaction is

A
1/4

B
1/3

C
1/2

D
1
Question 5
4 / -1

Formaldehyde polymerises to form glucose according to the reaction, 6 HCHO ⇌ C₆H₁₂O₆.
The theoretically computed equilibrium constant for this reaction is found to be 6 x 10²². If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

A
1.6 × 10^-2 M

B
1.6 × 10^-4 M

C
1.6 × 10^-6 M

D
1.6 × 10^-8 M
Question 6
4 / -1

In chemical equilibrium, the value of ∆n (number of molecules of products - number of molecules of reactants), is negative, then the relationship between K_P and K_C will be

A
K_P - K_C = 0

B
K_P - K_C (RT)^+∆n_g

C
K_P - K_C (RT)^-∆n

D
K_P = 1/K_C
Question 7
4 / -1

Three moles of PCl₅, three moles of PCl₃ and two moles of Cl₂ are taken in a closed vessel. If at equilibrium, the vessel has 1.5 moles of PCl₅, the number of moles of PCl₃ present in it is

A
5

B
3

C
6

D
4.5
Question 8
4 / -1

2HI (g) ⇌ H₂ (g) + I₂ (g) - QkJ
For the above reaction, equilibrium constant depends upon

A
temperature

B
pressure

C
catalyst

D
volume
Question 9
4 / -1

In the reaction H₂ (g) + Cl₂ (g) ⇌ 2HCl (g)

A
K_P ≠ K_C

B
K_P = K_C

C
K_P > K_C

D
K_P < K_C
Question 10
4 / -1

On doubling P and V with constant temperature, the equilibrium constant will

A
remain constant

B
become double

C
become one - forth

D
None of the above

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Chemical Equilibrium Test - 10

Result

Chemical Equilibrium Test - 10

Score

-

Rank

-

SHARING IS CARING

Question 1

Rate of forward reaction =Rate of backward reaction

Equilibrium is dynamic

Catalysts increase the value of equilibrium constant

Free energy change is zero

Question 2

1

3

4

9

Question 3

6.25

25

250

500

Solution

Question 4

1/4

1/3

1/2

1

Question 5

1.6 × 10-2 M

1.6 × 10-4 M

1.6 × 10-6 M

1.6 × 10-8 M

Question 6

KP - KC = 0

KP - KC (RT)+∆ng

KP - KC (RT)-∆n

KP = 1/KC

Question 7

5

3

6

4.5

Question 8

temperature

pressure

catalyst

volume

Question 9

KP ≠ KC

KP = KC

KP > KC

KP < KC

Question 10

remain constant

become double

become one - forth

None of the above

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.

1.6 × 10^-2 M

1.6 × 10^-4 M

1.6 × 10^-6 M

1.6 × 10^-8 M

K_P - K_C = 0

K_P - K_C (RT)^+∆n_g

K_P - K_C (RT)^-∆n

K_P = 1/K_C

K_P ≠ K_C

K_P = K_C

K_P > K_C

K_P < K_C