Thermodynamics Test

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Thermodynamics Test - 40

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Weekly Quiz Competition

Question 1
4 / -1

A solution of 500 ml. of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and stirred; the rise in temperature is T₁. The experiment is repeated using 250 ml each of solution, the temperature rise is T₂. Which of the following is true?

A
T₁ = T₂

B
T₁ = 2T₂

C
T₁ = 4T₂

D
T₂ = 9T₁

Solution
Question 2
4 / -1

Enthalpy of a reaction at 27^oC is 15 kJ mol^-1. The reaction will be feasible if entropy is

A
15 J mol^-1K^-1

B
– 50 J mol^-1 K^-1

C
greater than 5 J mol^-1 K^-1

D
less than 50J mol^-1K^-1
Question 3
4 / -1

The occurrence of reaction is impossible if

A
∆H is +ve ; ∆S is also +ve

B
∆H is –ve ; ∆S is also –ve

C
∆H is –ve ; ∆S is +ve

D
∆H is +ve ; ∆S is –ve
Question 4
4 / -1

Heat of neutralisation of a strong acid and a strong base is nearly equal to

A
10 kJ /mole

B
10Cal/mole

C
-57KJ/mole

D
-57Cal/mole
Question 5
4 / -1

For the transition C (diamond) → C (graphite) ; ∆H = ‒ 1.5 kJ. It follows that

A
diamond is exothermic

B
graphite is endothermic

C
graphite is stabler than diamond

D
diamond is stabler than graphite
Question 6
4 / -1

Which of the following is an endothermic reaction?

A
2H₂ + O₂ → 2H₂O

B
N₂ + O₂ → 2NO

C
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

D
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
Question 7
4 / -1

The heat released when NH₄OH and HCl neutralise is

A
13.7 kcal

B
>13.7 kcal

C
< 13.7 kcal

D
none of the above
Question 8
4 / -1

A
∆H₁ > ∆H₂

B
∆H₁ = ∆H₂

C
∆H₁ < ∆H₂

D
∆H₁ + ∆H₂ = 0
Question 9
4 / -1

For which one of the following reactions will there be a +ve ∆S ?

A
H₂O(g) → H₂O(l)

B
H₂ + I₂ → 2HI

C
CaCO₃(s) → CaO(s) + CO₂(g)

D
N₂(g) + 3H₂(g) →2NH₃(g)
Question 10
4 / -1

In which of the following reactions does the heat change represent the heat of formation of water?

A

B

C

D

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Thermodynamics Test - 40

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Thermodynamics Test - 40

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Question 1

T1 = T2

T1 = 2T2

T1 = 4T2

T2 = 9T1

Solution

Question 2

15 J mol-1K-1

– 50 J mol-1 K-1

greater than 5 J mol-1 K-1

less than 50J mol-1K-1

Question 3

∆H is +ve ; ∆S is also +ve

∆H is –ve ; ∆S is also –ve

∆H is –ve ; ∆S is +ve

∆H is +ve ; ∆S is –ve

Question 4

10 kJ /mole

10Cal/mole

-57KJ/mole

-57Cal/mole

Question 5

diamond is exothermic

graphite is endothermic

graphite is stabler than diamond

diamond is stabler than graphite

Question 6

2H2 + O2 → 2H2O

N2 + O2 → 2NO

2NaOH + H2SO4 → Na2SO4 + 2H2O

C2H5OH + 3O2 → 2CO2 + 3H2O

Question 7

13.7 kcal

>13.7 kcal

< 13.7 kcal

none of the above

Question 8

∆H1 > ∆H2

∆H1 = ∆H2

∆H1 < ∆H2

∆H1 + ∆H2 = 0

Question 9

H2O(g) → H2O(l)

H2 + I2 → 2HI

CaCO3(s) → CaO(s) + CO2(g)

N2(g) + 3H2(g) →2NH3(g)

Question 10

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T₁ = T₂

T₁ = 2T₂

T₁ = 4T₂

T₂ = 9T₁

15 J mol^-1K^-1

– 50 J mol^-1 K^-1

greater than 5 J mol^-1 K^-1

less than 50J mol^-1K^-1

2H₂ + O₂ → 2H₂O

N₂ + O₂ → 2NO

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

∆H₁ > ∆H₂

∆H₁ = ∆H₂

∆H₁ < ∆H₂

∆H₁ + ∆H₂ = 0

H₂O(g) → H₂O(l)

H₂ + I₂ → 2HI

CaCO₃(s) → CaO(s) + CO₂(g)

N₂(g) + 3H₂(g) →2NH₃(g)