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    Let f(x) = (x2 − 1) n (x2 + x + 1), then f(x) has local extremum at x = 1 when least value of n :

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    The number of solutions of the equation af(x) + g(x) = 0, where a > 0, g(x) ≠ 0 and has minimum value ½ is

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    A curve passes through the point (2, 0) and the slope of the tangent at any point (x, y) is x2 − 2x for all values of x. The point of maximum ordinate on the curve is :

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