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Weekly Quiz Competition
  • Question 1
    1 / -0

    There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

    Solution

    Required no. of ways = 3C2 × 9C2 = 3 × 36 = 108.

  • Question 2
    1 / -0

    Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from 10 white, 9 green and 7 black balls is

    Solution

    First, one can select from 0 to 10 white balls in (10+1) ways.

    Then, you can select from 0 to 9 green balls in (9+1) ways.

    Finally, you can select from 0 to 7 red balls in (7+1) ways.

    Hence the total number of choices = (10+1)(9+1)(7+1)

    Now, this also includes 1 situation in which none of the balls is selected. Since we need to select atleast 1 ball, we will need to subtract that.

    Therefore, number of ways of selecting one or more balls from 10 white, 9 green, and 7 black balls = (10 + 1) (9 + 1) (7 + 1) – 1 = 11×10 × 8 – 1 = 879. 

    Hence, option D is correct.

  • Question 3
    1 / -0

    A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is

    Solution

    Number of choices = 5C4 × 8C6 + 5C5 × 8C5 
    = 140 + 56 = 196.

  • Question 4
    1 / -0

    From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on a shelf so that the dictionary is always in the middle. Then the number of such arrangements is

    Solution

    N1N2N3 – N6, D1D2D3 
    The number of ways = 6c4 × 3c1 × 24 × 4 
    = 15 × 3 × 24 × 4 = 1080 × 4 
    Hence, option D is correct.

  • Question 5
    1 / -0

    Statement-1: The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is 9C3 
    Statement-2: The number of ways of choosing any 3 places from 9 different places is 9C3.

    Solution

    ∴ The number of ways of distributing n identical objects among r persons such that each person gets at least one object is same as the number of ways of selecting (r - 1) places out of (n-1) different places, that is n-1Cr-1. Therefore, statement 1 is true, and statement 2 is true but statement 2 is not the correct reason or explanation for statement 1. Hence, option B is correct.

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