Chemistry Test 115

Result

Chemistry Test 115

Score
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Weekly Quiz Competition

Question 1
4 / -1

The energy profile of the given reaction.

A
(1)

B
(2)

C
(3)

D
(4)

Solution
Question 2
4 / -1

A
an optically active compound

B
an optically inactive compound

C
a racemic mixture

D
a diastereomeric mixture

Solution
Question 3
4 / -1

A C₇H₁₄O optically active alcohol is oxidized by Jones’ reagent (H₂CrO₄) to an optically inactive (achiral) ketone. Which of the following compounds meets these facts?

A
(1)

B
(2)

C
(3)

D
(4)

Solution
Question 4
4 / -1

Which of the following set of quantum numbers represent the highest energy of an atom :-

A
n = 3,   ℓ = 1,   m = 1,   s = + 1/2

B
n = 3,   ℓ = 2,   m = 1,   s = + 1/2

C
n = 4,   ℓ = 0,   m = 0,   s = + 1/2

D
n = 3,   ℓ = 0,   m = 0,   s = + 1/2
Question 5
4 / -1

During adsorption the ΔH is –ve and the magnitude of –ve value

A
goes on increasing

B
goes on decreasing

C
remains same

D
first increase then decreases

Solution

During adsorption the –ve value of ΔH goes on decreasing because as adsorption proceeds number of adsorption sites decreases and hence exothermicity decreases.
Question 6
4 / -1

pH of a mixture of 1 M HA (pK_a = 4.2) and 1 M NaA is 4.5. In 300 ml of buffer volume of HA is [log 2 = 0.3]

A
200 ml

B
150 ml

C
100 ml

D
600 ml

Solution
Question 7
4 / -1

If the anions (A) form hexagonal closest packing and cations (C) occupy only 2/3 of the octahedral voids in it, then the general formula of the compound would be

A
CA

B
CA₂

C
C₂A₃

D
C₃A₂

Solution

In HCP, the number of octahedral void is equal to the number of atoms. Hence, the formula is AC_2/3 i.e. A₃C₂.
Question 8
4 / -1

On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is :

A
< 50 mL

B
> 50 mL

C
= 50 mL

D
Cannot be predicted

Solution

Acetone and chloroform forms hydrogen bonding so volume decreases.
Question 9
4 / -1

Calculate the internal energy change of one mole of an ideal gas during an adiabatic free expansion process from a volume of 2 litre to 5 litre.

A
0.6 J

B
80.79 J

C
60.79 J

D
Zero
Question 10
4 / -1

At 67ºC and 1 bar pressure, dinitrogen tetra oxide is 50% dissociated into nitrogen dioxide. ΔGº for the process :

2NO₂(g) ⇌ N₂O₄(g) is -

(R = 25/3 J/K.mol, ln2 = 0.7, ln3 = 1.1)

A
–850 Jmol^–1

B
+850 Jmol^–1

C
–850 kJmol^–1

D
+850 kJmol^–1