Chemistry Test 119

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Chemistry Test 119

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Weekly Quiz Competition

Question 1
4 / -1

Which of the following set of all quantum number is correct for the last e^– that enters in Fe.

A
n = 4, ℓ = 0, m = 0, s = +

B
n = 3, ℓ = 1, m = 0, s = -

C
n = 3, ℓ = 2, m = –1, s = +

D
n = 4, ℓ = 1, m = 0, s = -

Solution
Question 2
4 / -1

Find the incorrect acidic strength order

A
K₂O > Rb₂O > Cs₂O

B
N₂O₅ < NO₂ < N₂O₃

C
Li₂O < BeO < N₂O₅

D
Cl₂O₇ > P₂O₅ > SiO₂
Question 3
4 / -1

Which of the following is INCORRECT statement ?

A
In adiabatic expansion of an ideal gas, temperature of system always decrease

B
In isothermal expansion of an ideal gas, temperature of a gas always remains constant

C
In a reversible adiabatic compression of an ideal gas, change in entropy of system is zero

D
In an irreversible adiabatic compression of an ideal gas, change in entropy of system is positive

Solution

In adiabatic free expansion temperature does not change.
Question 4
4 / -1

Calculate the magnitude of net work done in the following cycle for one mol of an ideal gas in Calorie. Where in process BC, PT = constant. (R = 2cal/mol-K)

A
800 cal

B
200 cal

C
300 cal

D
400 cal

Solution

w_total=w_AB + w_BC + w_CA

w_AB = 0 (isochoric)

w_CA = –nRΔT (isobaric)

= –1 × 2 × –800 = 1600 Cal

w_total=0 – 2400 + 1600 = –800 Cal
Question 5
4 / -1

Which of the following statements is/are correct ?

A
Ca²⁺ has a smaller ionic radius than K⁺

B
2p^- orbital is lower in energy than 2s of Be atom

C
F is more electronegative than Cl atom

D
option 1 and option 3 are correct
Question 6
4 / -1

Which of the following set of quantum number is/are not possible for Ac?

A
n = 3, l = 3, m = 0, s = +

B
n = 6, l = 2, m = –1, s = -

C
n = 6, l = 3, m = –2, s = +

D
option 1 and option 3 are correct
Question 7
4 / -1

For the change -

R → P ; ΔH = –ve

If above reaction increase the disorderness of system then -

A
ΔH_f(P) > ΔH_f (R)

B
ΔHC(P) > ΔHC (R)

C
ΔS_f(P) > ΔS_f (R)

D
option 2 and option 4 are correct

Solution

R → P ΔH = –ve, ΔS = +ve

(A) ΔH = Δ_fH_(P) – Δ_fH_(R) < 0
Δ_fH_(P) < Δ_fH_(R)

(B) ΔH = Δ_CH_(R) – Δ_CH_(P) < 0
Δ_CH_(P) > Δ_CH_(R)

(D) ΔS = +ve
Δ_fS_(P) – Δ_fS_(R) > 0
Δ_fS_(P) > Δ_fS_(R)
So, B, D
Question 8
4 / -1

Consider the following reaction :

2Fe₂O₃(s) + 3C(s) → 4Fe(s) + 3CO₂(g)

ΔH_f^º of Fe₂O₃ & CO₂ are –820 kJ/mol and –390 kJ/mol respectively.

The reaction is -

A
Endothermic

B
Exothermic

C
Spontaneous at high temperature

D
option 1 and option 3 are correct

Solution

ΔH = 3 × (–390) – 2 (–820)

= 470 kJ/mol

ΔG < 0 ΔH – T ΔS < 0

for spontaneous reaction → T ΔS > ΔH

(∵ ΔS > 0)