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Chemistry Test 138

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Chemistry Test 138
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Weekly Quiz Competition
  • Question 1
    4 / -1

    (i)  Tensile strength of vulcanised rubber is almost ten times more than raw rubber.

    (ii)  Elasticity of raw rubber is very high.

    Choose the correct option.

    Solution

    Natural rubber is soft and sticky and after vulcanisation its strength increases due to cross linked formed between different 

     

  • Question 2
    4 / -1

    The correct order of reducing ability for the four successive elements Cr, Mn, Fe and Co is: Their Eored values are given below.

    Solution

    The values of Eored gives us an idea of the ease with which metals get reduced. A higher negative value implies that it has greater tendency to get oxidised. 

    For a metal to act as a reducing agent, it should itself get oxidised. Hence, the order of reducing ability is proportional to ease of oxidation which is inversly proportional to Eored. 
    Hence, the answer will be:
    Mn > Cr > Fe > Co

     

  • Question 3
    4 / -1

    An unknown alkyl halide (A) reacts with alcoholic KOH to produce a hydrocarbon (C4H8) as the major product. Ozonolysis of the hydrocarbon affords one mole of propanaldehyde and one mole of formaldehyde. Suggest which organic compound among the following has the correct structure of the above alkyl halide (A)?

    Solution

    Since the product on ozonolysis is propanaldehyde and formaldehyde, it implies that the the double bond is shared between C1 and C2.

    If the compound were option 1, the result of such elimination would have been 2 butene whose ozonolysis would give ethanals

    1- butene on ozonolysis gives propanaldehyde and formaldehyde thus the hydrocarbon is
    CH3CH2CH = CH2 
    (C4H8) 1-butene
    1 butene can be obtained by

     

  • Question 4
    4 / -1

    Which one of the following reactions of Xenon compounds is not feasible?

    Solution

    The reaction XeO3+6HF⟶XeF6+3H2O is not feasible because XeF6 formed will further produce XeO3 by getting hydrolysed.
    XeF6 + H2O → XeOF4 + 2HF
    XeOF4 + H2O → XeO2F2 + 2HF
    XeO2F2 + H2O → XeO3 + 2HF

     

  • Question 5
    4 / -1

    One mole of a non-ideal gas undergoes a change of state(2.0 atm, 3.0 L, 95 K) ⟶ (4.0 atm, 5.0 L, 245 K) with a change in internal energy, ΔE = 30.0 L-atm. The change in enthalpy (ΔH) of the process in L-atm

    Solution

    H = E+PVH
    ΔH = ΔE+Δ(PV)
    = ΔE+(P2V2−P1V1)
    = 30.0+(4×5−2×3)
    = 30.0+14.0
    = 44 L atm.

     

  • Question 6
    4 / -1

    How many moles of KMnO4 are needed to oxidise a mixture of 1 mole each of FeSO4, FeC2O4 and Fe2(C2O4)3 completely in acidic medium :

    Solution


     

  • Question 7
    4 / -1

    The catalyst used in the manufacture of polyethylene by Ziegler method is

    Solution

    Ziegler - Natta catalyst is used in polymerisation of ethene : (C2H5)3 Al + TiCl4.

     

  • Question 8
    4 / -1

    The reagent with which both acetaldehyde and acetone react easily is

    Solution

    Grignard’s reagent reacts with both aldehydes and ketones while other three reagents reacts only with aldehydes, not with ketones.

     

  • Question 9
    4 / -1

    Which of the following facts about the complex [Cr(NH3)6]Cl3 is wrong?

    Solution

    The complex [Cr(NH3)6]Cl3 involves d2sp3 hybridization as it involves (n - 1)d orbitals for hybridization. It is an inner orbital complex.

     

  • Question 10
    4 / -1

    Consider the reaction 2NO(g)+O2(g) ⟶ 2NO2(g) Predict whether the reaction is spontaneous at 298 K. ΔfG(NO) = 86.69kJ/mol,ΔfG(NO2) = 51.84kJ/mol

    Solution

    2NO(g)+O2(g) ⟶ 2NO2(g)
    ΔG = 2ΔfG(NO2)−[2ΔfG(NO)+ΔfG(O2)]
    = (2×51.84)−(2×86.69+0)
    = 103.68−173.38
    = −69.7kJ/mol ; Δ G is negative
    So the reaction is spontaneous

     

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