Chemistry Test 157

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Chemistry Test 157

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Question 1
4 / -1

Ag|AgBr |Br–||Fe³⁺, Fe²⁺|Pt

0.34M 0.1M 0.02M

AgBr + e^– → Ag + Br^– E° = 0.0713V

Fe³⁺ + e^–→ Fe²⁺ E° = 0.77V

Find emf of cell at 25°C

A
0.474 V

B
0.529 V

C
0.356 V

D
0.713 V

Solution

Ag + Br^– → AgBr + e^–

Fe³⁺ + e^– → Fe²⁺

Ag + Fe³⁺ + Br^– → AgBr + Fe²⁺
Question 2
4 / -1

Directions For Questions

Consider the plots, given below, for the type of reaction, A → B + C

...view full instructions

These plots respectively corresponds to the reaction order :-

A
0, 1, 2

B
1, 2, 0

C
1, 0, 2

D
None of these

Solution
Question 3
4 / -1

An element 'A' in a compound ABD has oxidation number –n. It is oxidised by Cr₂O₇^2– in acidic medium. In the experiment 1.68 × 10^–3 moles of K₂Cr₂O₇ were used for 3.36 × 10^–3 moles of ABD. The new oxidation number of A after oxidation is :-

A
3

B
3 – n

C
n – 3

D
+ n

Solution

2Cr³⁺ + Ay

Total oxidation = Total Reduction

(3.26 × 10^–3) (y – (–n)) = (1.68 × 10^–3) × 6

2 × y + n = 63

y = 3 – n
Question 4
4 / -1

Arrange the resonating structures of CH₂N₂ in increasing order of stability.

A
II > I > IV > III

B
I > II > IV > III

C
III > II > IV > I

D
IV > II > III > I

Solution

(A) II > I > IV > III

(ii) Octet complete according to charge dispersion rule.

(i) Octet complete but – ve charge present at less electronegative atom.

(iv) – ve charge stable at more electronegative

(iii) –ve charge less stable at less electronegative atom
Question 5
4 / -1

The final product P is -

A

B

C

D

Solution
Question 6
4 / -1

Directions For Questions

In the following reaction, three products a,b,c are obtained.

...view full instructions

The approximate experimental yields of the three compounds were 64%, 33% and 3%. Which of the following is the correct with respect to yield and the corresponding product?

A
(a) 33% ; (b) 64% ; (c) 3%

B
(a) 3% ; (b) 64% ; (c) 33%

C
(a) 3% ; (b) 33% ; (c) 64%

D
(a) 64% ; (b) 3% ; (c) 33%
Question 7
4 / -1

The major product obtained when Br₂/Fe is treated with

A

B

C

D

Solution

The benzene ring to which >NH group is directly attached is activated for the attack of Br⁺ as –NH group is highly ringh activating due to +R effect, the ring to which group is directly attached is deactivated towards electrophillic substitution. As group is ring deactivating due to –R effect in addition the group is ortho-para directing but para position is favourable for the attach of Br⁺. Hence the product formed is as follows
Question 8
4 / -1

Major product

A

B

C

D

Solution
Question 9
4 / -1

In the following reaction sequence, structures of P and Q, are respectively

A

B

C

D

Solution
Question 10
4 / -1

The pyrimidine bases present in DNA are

A
Cylosine and Uracil

B
Cytosine and Thymine

C
Cytosine and Guanine

D
Cytosine and Adenine

Solution

In DNA four bases are present adenine(A), guanine(G), cytosine (C) and thymine (T). Out of which pyrimidine bases are cytosine and thymine