JEE Advanced Mix Test 12

Result

JEE Advanced Mix Test 12

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

Graph shows a hypothetical speed distribution for a sample of N gas particles (for V > V0 ;

A
The value of aV_{0 is 2N.}

B

C

D
All are correct

Solution
Question 2
4 / -1

Pick the correct statement(s) :

A
The rms translational speed for all ideal-gas molecules at the same temperature is not the same but it depends on the mass.

B
Each particle in a gas has average translational kinetic energy and the equation establishes the relationship between the average translational kinetic energy per particle and temperature of an ideal gas. It can be concluded that single particle has a temperature.

C
Temperature of an ideal gas is doubled from 100°C to 200°C. The average kinetic energy of each particle is also doubled.

D
It is possible for both the pressure and volume of a monoatomic ideal gas to change simultaneously without causing the internal energy of the gas to change.

Solution

Since PV = nRT therefore P and V both can change simultaneously keeping temperature constant.
Question 3
4 / -1

STATEMENT–1: A gas is kept in an insulated cylinder with a movable piston, in compressed state. As the piston is released, temperature of the gas decreases.

STATEMENT–2: According to the kinetic theory of gas, a molecule colliding with the piston must rebound with less speed than it had before the collision. Hence average speed of the molecules is reduced.

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

C
Statement-1 is True, Statement-2 is False

D
Statement-1 is False, Statement-2 is True.

Solution

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
Question 4
4 / -1

Statement-1: As the temperature of the blackbody increases, the wavelength at which the spectral intensity (Eλ) is maximum decreases.

Statement-2: The wavelength at which the spectral intensity will be maximum for a black body is proportional to the fourth power of its absolute temperature.

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

C
Statement-1 is True, Statement-2 is False

D
Statement-1 is False, Statement-2 is True.

Solution

From Wein's law λ_mT = constant i.e., peak emission wavelength

Hence as T increase λ_m decreases.
Question 5
4 / -1

Directions For Questions

The atmospheric lapse rate For small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.

The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.

The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.

Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantity TP(1 – λ)/λ has a uniform value through the layers of troposphere. (M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)

...view full instructions

If behaviour of the mixing of parcels of air is approximately assumed to be adiabatic then lapse rate can be expressed as :

A

B

C

D

Solution
Question 6
4 / -1

Directions For Questions

The atmospheric lapse rate For small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.

The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.

The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.

Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantity TP(1 – λ)/λ has a uniform value through the layers of troposphere. (M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)

...view full instructions

Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to Assuming free fall acceleration to be uniform, then lapse rate is given by

A

B

C

D

Solution
Question 7
4 / -1

Directions For Questions

The atmospheric lapse rate For small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.

The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.

The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.

Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantity TP(1 – λ)/λ has a uniform value through the layers of troposphere. (M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)

...view full instructions

The value of theoretical lapse rate on the earth is (use g = 9.8 m/s² ; R = 8.3 J/mol-k and M = 29 g/mol)

A
– 9.8 K/km

B
– 9.8 K/m

C
– 6.7 K/km

D
– 3.4 K/km

Solution
Question 8
4 / -1

The figures given below show different processes (relating pressure P and volume V) for a given amount of an ideal gas. ΔW is work done by the gas and ΔQ is heat absorbed by the gas.

A
(A) s,t (B) p, r (C) q, s (D) s, t

B
(A) p, s (B) s, t (C) p, s (D) q, r

C
(A) q, r (B) p, s (C) s, t (D) p, s

D
(A) r (B) t (C) q, r, t (D) s, q

Solution
Question 9
4 / -1

The hybridisation and geometry of the anion of ICl₃ in liquid phase is :

A
sp³ and bent

B
sp³d² and square planar

C
sp³d and see–saw

D
sp³ and tetrahedral

Solution
Question 10
4 / -1

Select the incorrect statement about the XeF₆.

A
It has capped octahedron or distorted octahedral structure with one lone pair.

B
In various non-aqueous solvents it forms a tetramer Xe₄F₂₄.

C
Solid Xenon hexafluoride is polymorphic.

D
None of these

Solution

In tetramer, four square pyramidal XeF₅⁺ ions are joined to two similar ions by means of two bridging F^- ions.

The Xe-F distances are 1.84 Å on the square pyramidal units and 2.23 Å and 2.60 Å in the bridging groups. The solid has various crystalline forms, of which three are tetrameric and a fourth has both hexamers and tetramers.