Self Studies
Selfstudy
Selfstudy

JEE Advanced Mi...

TIME LEFT -
  • Question 1
    4 / -1

    A metallic wire is shaped in the form of a circle with a radius of 2 cm and is placed on a horizontal non-conducting surface. A uniform magnetic field of B = 10 T is present in the region surrounding the circular wire and is directed vertically.

    A conducting rod shown in red color, starting from x axis on the circular wire, slides along the wire while touching its length on the circumference of the circle. The equation of the circular wire is given as:

    (x - 4)2 + y2 = 4

    The rod moves with a uniform velocity, and the induced EMF in the rod reaches 5 V after 0.4 seconds.

    Determine the velocity of the rod required to induce an EMF of 5 V in a magnetic field of 5 T after 0.4 seconds.

  • Question 2
    4 / -1

    Aman has a rod of length ℓ meters . He wants to make a project on rotational motion and needs to check for the breaking stress of the rod. The rod has the following properties:

    • Mass = 8.7 kg
    • radius = 2 cm
    • Breaking Strength (σ) = 8 × 1011 Pa
    • Angular frequency (ω) = 10⁶ rad/s

    The rod is rotated about its center in a horizontal orientation . Aman wants to determine the maximum allowable length (ℓ) of the rod before it breaks due to rotational stress.

    What should be the maximum value of ℓ to prevent breaking?

  • Question 3
    4 / -1

    The internal energy (U) of an ideal gas depends on pressure (P) and volume (V) according to the equation:

    P = 2UV-1

    Based on this equation, which of the following conclusions can be drawn about the gas?

  • Question 4
    4 / -1

    Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance RP = 1Ω as shown in the figure. An external resistance of Re = 2Ω is connected via the sliding contact.

  • Question 5
    4 / -1

  • Question 6
    4 / -1

    Directions For Questions

    The solubility of alkaline earth metal sulphates in water decrease in the order

    BeSO4 > MgS4, > CaSO4 > SrSO4 > BaSO4. This is because

    (A) Hydration energy increases down the group

    (B) The rate of decrease of hydration energy is higher than the rate of decrease of lattice energy

    (C) Lattice energy increases down the group

    (D) Hydration energy of Be+ and Mg" are very high

    (E) Covalency is increasing down the group

    ...view full instructions

    Choose the correct answer from the options given below:

  • Question 7
    4 / -1

    The major product in the following reaction is:

  • Question 8
    4 / -1

  • Question 9
    4 / -1

  • Question 10
    4 / -1

Submit Test
Self Studies
User
Question Analysis
  • Answered - 0

  • Unanswered - 10

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Submit Test
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now