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Mathematics Test 131

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Mathematics Test 131
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Weekly Quiz Competition
  • Question 1
    4 / -1

    If statement (P →q) → (q →r) is false, then truth values of statements p,q and r respectively can be

    Solution

    If (P →q) →(q →r) is false then (p →q) must be true and (q →r) must be false.
    Now,
    If P →q is true then P & q both can be true or false :
    If q →r is false then q must be true and r must be false
    So when both condition i.e. P →q true and q → r false satisfy then q is truer is false and P can be true or false 

     

  • Question 2
    4 / -1

    A mirror and a source of light are situated at the origin O and at a point on OX respectively. A ray of light from the source strikes the mirror and is reflected. If the direction ratios of the normal to the plane are proportional to 1, –1, 1 then direction cosines of the reflected ray are

    Solution

    Let the source of light be situated at A(a,0,0) where  a≠0

    Let OA be the incident ray, OB be the reflected ray and ON be the normal to the mirror at O.

    Direction ratio of  are proportional to a, 0, 0 and so its direction cosines are 1, 0, 0.

    Direction cosines of ON are 

    Hence, direction cosines of the reflected ray are 

     

  • Question 3
    4 / -1

    Solution

     

  • Question 4
    4 / -1

    Find the differential equation of the family of ellipse such that its centre is on the origin

    Solution

     

  • Question 5
    4 / -1

    If  then range of f(x) is -

    Solution

    so

     

  • Question 6
    4 / -1

    The eccentricity of an ellipse with its centre at the origin is 1/2. If one of the directrix is x = 4, then the equation of the ellipse is

    Solution

     

  • Question 7
    4 / -1

    The greatest value of λ ≥ 0 for which both the equations 2x2 + ( λ − 1)x + 8 = 0 and x2 − 8x + λ + 4 = 0 have real roots is

    Solution

     

  • Question 8
    4 / -1

    The number of pairs of solution of the system of equations x+y=2π/3, cosx+cosy=3/2 where x and y are real is

    Solution

    We write the second equation as

    Since, the range of cos function is [-1,1], so no values of x and y satisfy the second equation.
    x∈φ, y∈φ

     

  • Question 9
    4 / -1

    The mean of n terms is  If first term is increased by 1, second term by 2, and so on, then new mean is

    Solution

     

  • Question 10
    4 / -1

    The points of contact of the tangents drawn from the origin to the curve y = sin x lie on the curve

    Solution

    1. Let (h, k) be a point of contact of the tangents drawn from the origin to y = sin x. Then, (h,k) lies on y = sin x..
    ∴k = sin h …(i)

    Now,

    The equation of the tangent at (h,k) is
    y – k = (cos h) (x – h)
    This passes through (0,0).

     

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