JEE Main Test 67

Result

JEE Main Test 67

Score
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Rank
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Weekly Quiz Competition

Question 1
4 / -1

Among the following the maximum covalent character is shown by the compound

A
FeCl₂

B
SnCl₂

C
AlCl₃

D
MgCl₂

Solution

In inorganic chemistry, Fajan’s rules are used to predict whether a chemical bond will be covalent or ionic and depending on the charge on the cation and the relative sizes of the cation and anion.

Here, in the given compounds, Cl^- is there in all decided by size and charge of the cation. Therefore higher the charge of the cation, smaller will be the size of the cation, then more will be the polarizing power.

Hence among all the compounds Al khas maximum of +3 oxidation state, hence AlCl₃ has the maximum covalent charcater.
Question 2
4 / -1

The molecule having smallest bond angle is

A
NCl₃

B
AsCl₃

C
SbCl₃

D
PCl₃

Solution

Here,

NCl₃ → trigonal pyramidal →107⁰

ASCl₃→ trigonal pyramidal →109

SbCl₃ → pyramidal →97.20

PCl₃→ trigonal pyramidal → about 109.

Hence SbCl₃ has smaller bond angle is 97.2%.
Question 3
4 / -1

Two moles of oxygen is mixed with eight moles of helium. The effective specific heat of the mixture at constant volume is

A
1.3 R

B
1.4 R

C
1.7 R

D
1.9 R

Solution
Question 4
4 / -1

A
1 : 1

B
2 : 1

C
1 : 3

D
√3 : 1

Solution
Question 5
4 / -1

A
80

B
100

C
- 110

D
92

Solution
Question 6
4 / -1

For a body performing SHM, at a distance A ⁄ √2, then correct relation between KE and PE will be

A
KE is equal to PE

B
KE is 2 times of PE

C
KE is 3 times of PE

D
KE is half of PE

Solution
Question 7
4 / -1

A

B

C

D

Solution
Question 8
4 / -1

A
no real solution

B
one real solution

C
more than one solution

D
none of these

Solution
Question 9
4 / -1

A

B

C

D

Solution
Question 10
4 / -1

A charge 10 μC is placed at the centre of a hemisphere of radius R = 10 cm as shown. The electric flux through the hemisphere (in MKS units) is

A
20 × 10⁵

B
10 × 10⁵

C
6 × 10⁵

D
2 × 10⁵

Solution