JEE Main Test 70

Result

JEE Main Test 70

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Weekly Quiz Competition

Question 1
4 / -1

The synthesis of 3-octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne.
The bromoalkane and alkyne respectively are

A
BrCH₂ CH₂ CH₂ CH₂ CH₃ and CH₃ CH₂ C ≡ CH

B
BrCH₂ CH₂ CH₃ and CH₃ CH₂CH₂ C ≡ CH

C
BrCH₂ CH₂ CH₂ CH₂ CH₃ and CH₃ C ≡ CH

D
BrCH₂ CH₂ CH₂ CH₃ and CH₃ CH₂ C ≡ CH

Solution

3-octyne is obtained by the reaction of 1- bromobutane and but -1-yne in presence of sodamide.
Question 2
4 / -1

Bicyclo (1, 1, 0) butane is

A

B

C

D

Solution
Question 3
4 / -1

Experimentally it was found that a metal oxide has formula M_0.98 O. Metal M, present as M²⁺ and M³⁺ in its oxide. Fraction of the metal which exists as M³⁺ would be

A
7.01%

B
4.08%

C
6.05%

D
5.08%

Solution
Question 4
4 / -1

Which kind of defect is shown by the given crystal?

A
Schottky defect

B
Frenkel defect

C
Schottky and Frenkel defects

D
Substitution disorder

Solution

A schottky defect is a type of point defect in a crystal lattice. In non – ionic crystals it means a lattice vacancy defect.

In ionic crystals, the defect forms when oppositely charged ions leave their sites, creating vacancies. There vacancies are formed in stoichiometric units, to maintains an overall neutral change in the ionic solid. The vacancies are then free to move about their own entities. Normally these defects will lead to a decrease in the density of the crystal.
Question 5
4 / -1

Identify the binary mixture(s) that can be separated into individual compounds, by differential extraction as shown in the given scheme.

A
C₆H₅OH and C₆H₅, COOH

B
C₆H₅COOH and C₆H₅CH₂ OH

C
C₆H₅CH₂OH and C₆H₅OH

D
C₆H₅OH and C₆H₅CH₂COOH

Solution
Question 6
4 / -1

Given the limiting molar conductivity as
˄⁰_m (HCl) = 425.9Ω^-1 cm² mol^-1
˄⁰_m (NaCl) = 126.4Ω^-1 cm² mol^-1
˄⁰_m (CH₃ COONa) = 91Ω^-1 cm² mol^-1
The molar conductivity, at infinite dilution, of acetic acid (in Ω^-1 cm² mol^-1) will be

A
481.5

B
390.5

C
299.5

D
516.9

Solution
Question 7
4 / -1

29.2% (w/W) HCl stock solution has density of 1.25 g mL^-1. The molecular weight of HCl is 36.5 mol^-1. The volume (mL) of stock solution required to prepare a 200 mL solution 0.4 M HCl is

A
5.0 mL

B
6.0 mL

C
8.0 mL

D
15.0 mL

Solution
Question 8
4 / -1

A
Cl

B
Cr³⁺

C
Mn²⁺

D

Solution
Question 9
4 / -1

A
0.10 mol L^-1 s^-1

B
2.6 × 10^-2 mol L^-1 s^-1

C
5.2 × 10^-2 mol L^-1 s^-1

D
6.5 × 10^-3 mol L^-1 s^-1

Solution
Question 10
4 / -1

The standard emf of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25C°. The equilibrium constant of the reaction would be
(Given, F = 96500 C mol^-1, R = 8. 314 JK^-1 mol^-1 )

A
2.0 × 10¹¹

B
4.0 × 10¹²

C
1.0 × 10²

D
1.0 × 10¹⁰

Solution