JEE Main Test 87

Result

JEE Main Test 87

Score
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Rank
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Weekly Quiz Competition

Question 1
4 / -1

The intercept on the line y = x by the circle x² + y² - 2x = 0 is AB. Equation of the circle with AB as diameter is

A
x² + y² = 1

B
x(x - 1) + y(y - 1) = 0

C
x² + y² = 2

D
(x - 1) (x - 2) + (y - 1) (y - 2) = 0

Solution
Question 2
4 / -1

Which of the following relations is correct ?

A

B

C

D

Solution
Question 3
4 / -1

For EM wave propagating along X-axis, E_max = 30 Vm ^-1. What is maximum value of magnetic field?

A
10^-7 T

B
10^-8 T

C
10^-9 T

D
10^-6 T

Solution
Question 4
4 / -1

In the equation of state of an ideal gas pV = nRT , the value of the universal gas constant would depend only on

A
the nature of the gas

B
the pressure of the gas

C
the units of the measurement

D
None of the above

Solution

From an ideal equation,

pV = nRT

where, R is known as universal gas constant or molar gas constant.

Values of R = 0.0821 L atm K^–1 mol^–1

                    = 8.314 × 10⁷ ergs K^–1 mol^–1

                    = 8.314 J K^–1 mol^–1

                    = 1.987 = 2 cal K^–1 mol^–1

Hence, R is considered as a universal gas constant. It will not depend on pressure and nature of gas but depend only on the units of measurements.
Question 5
4 / -1

The parameters from of the ellipse 4(x + 1)² + (y - 1)² = 4 is

A
x = cos θ - 1, y = 2 sin θ - 1

B
x = 2cos θ - 1, y = sin θ + 1

C
x = cos θ - 1, y = 2 sin θ + 1

D
x = cos θ + 1, y = 2 sin θ + 1

Solution
Question 6
4 / -1

If I₀ is the intensity of the principal maximum in the single slit diffraction pattern, then what will be its intensity when the slit width is doubled ?

A
2I₀

B
4I₀

C
I₀

D
I₀ / 2

Solution
Question 7
4 / -1

A
- 393

B
+ 393

C
+ 655

D
- 655

Solution

If we add the given 3 equations, we get the equation, C(g) + O₂(g) → CO₂(g),

∆H = ?

∴ ∆H = (131 – 282 – 242) kJ

∆H = -393 kJ
Question 8
4 / -1

The normals at three points P, Q and R of the parabola y² = 4ax meet at (h, k). The centroid of the ∆PQR lies on

A
x = 0

B
y = 0

C
x = -a

D
y = a

Solution
Question 9
4 / -1

The equilibrium constant (K_C) for the reaction

N₂ (g) + O₂ (g) → 2NO (g) at temperature T, is 4 × 10^-4. The value of K_C for the reaction NO (g) → 1/2 N₂ (g) + 1/2 O₂ (g) at the same temperature is

A
0.02

B
2.5 × 10²

C
4 × 10^-4

D
50.0

Solution
Question 10
4 / -1

Amongst the following, the total number of compounds soluble in aqueous NaOH is

A
1

B
2

C
3

D
4

Solution