Thermal Expansion, Thermometry And Calorimetry Test

Result

Thermal Expansion, Thermometry And Calorimetry Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

The specific heat capacities of water, mercury, air and steam are 4186 J kg^–1 ^oC^–1, 138 J kg^–1 ^oC^–1, 1047 J kg^–1 ^oC^–1 and 2010 J kg^–1 ^oC^–1,respectively. Which one is the best coolant?

A
Water

B
Mercury

C
Air

D
Steam

Solution

Water is the best coolant.
Question 2
1 / -0

If 75 g of water at 100^oC is added to 20 g of ice at –15^oC, determine the resulting temperature. (Given that latent heat of ice = 80 cal g^–1 and specific heat of ice = 0.5 cal g^–1 ^oC^–1)

A
40.8^oC

B
60.5^oC

C
50.1^oC

D
70.7^oC

Solution

Let T = resulting temperature

Heat lost by 75 g water, mc ΔT = 75 x 1 x (100-T)

Heat gained by 20 g ice = Heat used to raise the temperature of ice from – 15^oC to 0^oC + Heat required to melt ice at 0^oC + Heat used to raise the temperature of water from 0^oC to T^oC.

= mc(0 + 15) + mL + mc(T – 0)

= 20 x 0.5 x 15 + 20 x 80 + 20 x 1 x T

= 1750 + 20T

Now, Heat gained = Heat lost

∴ 1750 + 20T = 75 (100 – T)

∴ T = 60.5^oC