Heat Transfer Test

Result

Heat Transfer Test - 1

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
1 / -0

Calculate the energy radiated per second from the filament of an incandescent lamp at 2000 K if the surface area is 5.0 x 10^–5 m² and its relative emittance is 0.85. (σ = 5.7 x 10^–8 W m^–2 K^–4)

A
68.78 J s^-1

B
52.36 J s^-1

C
47.21 J s^-1

D
38.76 J s^-1

Solution

Explanation:We know E = AeσT⁴

Here, A = 5.0 x 10^–5 m²

σ = 5.7 x 10^–8 W m^–2 K^–4

e = 0.85, T = 2000k

∴ E = 5.0 x 10^–5 m²x 0.85 x 5.7 x 10^–8 W^–2 K^–4x (2000)⁴K⁴

= 38.76 W = 38.76 J s^–1