Ray Optics Test

Result

Ray Optics Test - 143

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Weekly Quiz Competition

Question 1
4 / -1

A camera objective has an aperture diameter d. If the aperture is reduced to diameter d/2, the exposure time under identical conditions of light should be made

A

B

C

D

Solution
Question 2
4 / -1

A student can distinctly see the object upto a distance 15 cm. He wants to see the black board at a distance of 3 m. Focal length and power of lens used respectively will be

A
–4.8 cm, –3.3 D

B
–5.8cm, –4.3 D

C
–7.5 cm, –6.3 D

D
–15.8 cm,–6.3 D

Solution
Question 3
4 / -1

Image is formed for the short sighted person at

A
Retina

B
Before retina

C
Behind the retina

D
Image is not formed at all
Question 4
4 / -1

A man can see the objects upto a distance of one metre from his eyes. For correcting his eye sight so that he can see an object at infinity, he requires a lens whose power is

A
+0.5 D

B
+1.0 D

C
+2.0 D

D
–1.0 D

Solution
Question 5
4 / -1

A man can see the object between 15 cm and 30 cm. He uses the lens to see the far objects. Then due to the lens used, the near point will be at

A
10/3 cm

B
30 cm

C
15 cm

D
100/3cm

Solution
Question 6
4 / -1

The far point of a myopia eye is at 40 cm. For removing this defect, the power of lens required will be

A
40 D

B
– 4 D

C
–2.5 D

D
0.25 D

Solution
Question 7
4 / -1

Image formed on retina of eye is proportional to

A
Size of object

B
Area of object

C

D
Question 8
4 / -1

If the distance of the far point for a myopia patient is doubled, the focal length of the lens required to cure it will become

A
Half

B
Double

C
The same but a convex lens

D
The same but a concave lens

Solution
Question 9
4 / -1

A person uses a lens of power + 3 D to normalize vision.Near point of hypermetropic eye is

A
1 m

B
1.66 m

C
2 m

D
0.66 m

Solution
Question 10
4 / -1

In an eye-piece, field lens and eye lens have focal lengths 7.5 cm and 7.3 cm. To eliminate spherical aberration, distance between them would be

A
0.2 cm

B
0.4 cm

C
0.1cm

D
0.5 cm

Solution