Wave Optics Test

Result

Wave Optics Test - 32

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Weekly Quiz Competition

Question 1
4 / -1

In Young\'s double slit experiment, the fringe width is 1 × 10^–4 m. If the distance between the slit and screen is doubled and the distance between the two slit is reduced to half and wavelength is change from 6.4 × 10^–7m to 4.0 × 10^–7m, the value of new fringe width will be

A
0.15 × 10^–4 m

B
2.0 × 10^–4 m

C
1.25 × 10^–4 m

D
2.5 × 10^–4 m

Solution
Question 2
4 / -1

In Young\'s experiment, one slite is covered with a blue filter and the other (slit) with a yellow filter. Then the interference pattern

A
Will be blue

B
Will be yellow

C
Will be green

D
Will not be formed

Solution
Question 3
4 / -1

Two sources give interference pattern which is observed on a screen, D distance apart from the sources. Then fringe width is 2w. If the distance D is now doubled, the fringe width will

A
Become w/2

B
Remain the same

C
Become w

D
Become 4 w

Solution
Question 4
4 / -1

In double slit experiment, the angular width of the fringes is 0.20° for the sodium light (λ = 5890Å). In order to increase the angular width of the fringes by 10%, the necessary change in the wavelength is

A
Increase of 589 Å

B
Decrease of 589 Å

C
Increase of 6479 Å

D
Zero

Solution
Question 5
4 / -1

In a biprism experiment, by using light of wavelength 5000 Å, 5 mm wide fringes are obtained on a screen 1.0 m away from the coherent sources. The separation between the two coherent sources is

A
1.0 mm

B
0.1 mm

C
0.1 mm

D
0.01 mm

Solution
Question 6
4 / -1

The slits in a Young\'s double slit experiment have equal widths and the source is placed symmetrically relative to the slits. The intensity at the central fringes is I₀. If one of the slits is closed, the intensity at this point will be

A
I₀

B
I₀ / 4

C
I₀ / 2

D
4 I₀

Solution
Question 7
4 / -1

In a Young\'s double slit experiment, the fringe width will remain same, if (D = distance between screen and plane of slits. d = separation between two slits and λ = wavelength of light used)

A
Both λ and D are doubled

B
Both d and D are doubled

C
D is doubled but d is halved

D
λ is doubled but d is halved

Solution
Question 8
4 / -1

In a Young\'s double slit experiment the intensity at a point where the path difference λ/6 (λ being the wavelength of the light used) is I. If I₀ denotes the maximum intensity, I/ I₀ is equal to

A

B

C

D

Solution
Question 9
4 / -1

In Young\'s double slit experiment, angular width of fringes is 0.20° for sodium light of wavelength 5890 Å. If complete system is dipped in water, then angular width of fringes becomes

A
0.11°

B
0.15°

C
0.22°

D
0.30°

Solution
Question 10
4 / -1

In Young\'s double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be

A
5000 Å

B
6000 Å

C
7000 Å

D
8000 Å

Solution