Chemistry Test

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Chemistry Test - 9

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Weekly Quiz Competition

Question 1
4 / -1

Unit of rate constant of zero order reaction is

A
time^-1

B
mol lit^-1 sec^-1

C
liter mol^-1 sec^-1

D
liter² mol^-2sec^-1

Solution

According to rate law for zero order reaction,

Rate = K [A]⁰

= K = Mol L^-1s^-1

Thus, unit of rate constant is: Mol L^-1s^-1
Question 2
4 / -1

Which gas has the highest partial pressure in atmosphere?

A
CO₂

B
H₂O

C
0₂

D
N₂

Solution

Nitrogen is present in largest amount in the atmosphere. So it has the highest partial pressure in the atmosphere.
Question 3
4 / -1

Suppose that a sample of 100 g of water contains 0.025 g of chlorine. The concentration of chlorine in ppm will be

A
217 ppm

B
315 ppm

C
425 ppm

D
250 ppm

Solution

\(\frac{0.025 g}{100 g+0.025 g} \times 1,000,000=250 \mathrm{ppm}\)
Question 4
4 / -1

How many moles of Na₂S₂O₃ can be produced from 32 g of sulphur?

A
1.0

B
0.50

C
79

D
158

Solution

Number of moles of sulphur = 32/32 = 1 mole

One mole of Na₂S₂O₃ will be obtained from 2 moles of sulphur.

Mole of Na₂S₂O₃ obtained from 1 mole of sulphur = ½ = .50 mole
Question 5
4 / -1

The density of a gaseous substance at 1 atm pressure and 773 K is 0.4 g/l. If the molecular weight of the substance is 30 g, the forces existing among gas molecules are

A
repulsive

B
attractive

C
neutral

D
amphoteric

Solution

PV = ZnRT

Here, n (number of moles)=mass(W) / molar mass(M)

Then, PM=( W/V )ZRT

PM = ZdRT (where, M is molecular mass and d is density) [W/V=d (density)]

Substituting the values,

(1)(30) = Z(0.4)(0.082)(773)

Z = 1.183 > 1

Thus, forces are repulsive.
Question 6
4 / -1

The amount of Zn required to produce 224 ml of H₂ at STP on treatment with dilute H₂SO₄ will be

A
0.65g

B
6.5g

C
65g

D
0.065g

Solution

\(\mathrm{Zn}+\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \mathrm{ZnSO}_{4}+\mathrm{H}_{2}\)
\(224 \mathrm{cc} \mathrm{H}_{2}=0.65 \mathrm{g} \mathrm{Zn}\)
Question 7
4 / -1

Bredig's method can not be used for the preparation of collodial sol of

A
chromium

B
sodium

C
silver

D
gold

Solution

Bredig's method cannot be used for the preparation of colloidal sol of sodium as it does not give satisfactory results.
Question 8
4 / -1

Which of the following does not crystallise in the rock-salt structure?

A
NaCl

B
KCl

C
MgO

D
CsCl

Solution

CsCL has body-centred cubical packing.
Question 9
4 / -1

Which of the following sets of quantum numbers is correct for an electron in a 4f orbital?

A
n = 4, I = 3, m = 4, s = 1/2

B
n = 4, I = 4, m = 0, s = 1/2

C
n = 4, I = 2, m = -1, s = 1/2

D
n = 4, I = 3, m = -2, s = 1/2

Solution

The following set of quantum numbers is possible for an electron in a 4f orbital:

n = 4

l = 3

m = -3, -2, -1, 0, 1, 2, 3

s = +1/2 or -1/2

Hence, option (4) is correct.
Question 10
4 / -1

A 3d electron having s = +½ can have magnetic quantum number

A
+2

B
+3

C
-3

D
-4

Solution

3d electrons having s = +1/2 can have the following values of magnetic quantum number.

(-2, -1, 0, +1, +2)

Therefore, option (1) is the correct answer.

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Chemistry Test - 9

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Chemistry Test - 9

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SHARING IS CARING

Question 1

time-1

mol lit-1 sec-1

liter mol-1 sec-1

liter2 mol-2sec-1

Solution

Question 2

CO2

H2O

02

N2

Solution

Question 3

217 ppm

315 ppm

425 ppm

250 ppm

Solution

Question 4

1.0

0.50

79

158

Solution

Question 5

repulsive

attractive

neutral

amphoteric

Solution

Question 6

0.65g

6.5g

65g

0.065g

Solution

Question 7

chromium

sodium

silver

gold

Solution

Question 8

NaCl

KCl

MgO

CsCl

Solution

Question 9

n = 4, I = 3, m = 4, s = 1/2

n = 4, I = 4, m = 0, s = 1/2

n = 4, I = 2, m = -1, s = 1/2

n = 4, I = 3, m = -2, s = 1/2

Solution

Question 10

+2

+3

-3

-4

Solution

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time^-1

mol lit^-1 sec^-1

liter mol^-1 sec^-1

liter² mol^-2sec^-1

CO₂

H₂O

0₂

N₂