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  • Question 1
    4 / -1

    The two curves \(x^{3}-3 x y^{2}+2=0\) and \(3 x^{2} y-y^{3}-2=0\)

  • Question 2
    4 / -1

    \(\lim _{x \rightarrow 0} \frac{\sin x-x+\frac{x^{3}}{6}}{x^{5}}\) is equal to

  • Question 3
    4 / -1

    A relation from P to Q is

  • Question 4
    4 / -1

    \(3 \cos ^{-1} x-\pi x-\frac{\pi}{2}=0\) has :

  • Question 5
    4 / -1

    Let \(f(x)=\frac{2 \sin ^{2} x-1}{\cos x}+\frac{\cos x(2 \sin x+1)}{1+\sin x}\) then \(\int e^{x}\left(f(x)+f^{\prime}(x)\right) d x\) equals
    (where \(c\) is the constant of integeration)

  • Question 6
    4 / -1

    If the sum of two of the roots of x3 + px2 + qx + r = 0is zero, then pq =

  • Question 7
    4 / -1

    \(\int \frac{\cos ^{4} x d x}{\sin ^{3} x\left(\sin ^{5} x+\cos ^{5} x\right)^{\frac{3}{5}}}=-\frac{1}{2}\left(1+\cot ^{A} x\right)^{B}+C\) then \(\mathbf{A B}=\)

  • Question 8
    4 / -1

    \(\int \frac{(1+\sqrt{\tan x})\left(1+\tan ^{2} x\right)}{2 \tan x} d x\) equal \(\operatorname{to}\)

  • Question 9
    4 / -1

    sin-1 (sin 10 ) =

  • Question 10
    4 / -1

    The coefficient of x in the equation x2 + px + q = 0 was taken as 17 in place of 13, its roots were found to be -2 and -15, the roots of the original equation are

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