In the question, we are given the height at which water rises in a capillary tube of a certain diameter. Now the capillary tube is replaced by a similar tube of half the diameter of the previous tube. We are asked to find the height at which water will rise.
In order to answer this let us recall the expression for a surface of the liquid in a capillary tube which is given by,

Where, ℎ is the height at which the liquid rises in the capillary, y is the surface tension of the liquid, r is the radius of the capillary tube, p is the density of the liquid, g is the acceleration due to gravity and 0 is the angle of contact with the surface.
From this relation, we see that the height at which the liquid rises in the capillary is inversely proportional to the radius of the capillary tube, that is,

Let the diameter of the first capillary tube be d1, its radius be r1 and the height at which the liquid rises in the tube be ℎ1, then,

Now, let the diameter of the second capillary tube bed 2, its radius be r2 and the height at which the liquid rises in the tube be ℎ2, then,


But in the question, ℎ1 is given as h, therefore, the height at which the water will rise for a similar tube of half the diameter is found to be 4 h.
Hence, the correct answer is 4 h.