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Redox Reaction Test - 9

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Redox Reaction Test - 9
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  • Question 1
    1 / -0

    Direction (Q. Nos. 1-18) This section contains 18 multiple choice questions. Each question has four
    choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

    Q. Oxidation can be defined as the terms

    I. gain of electron and hydrogen
    II. gain of oxygen and loss of electron
    III. increase in oxidation number
    IV. decrease in oxidation number

    Select the correct terms

    Solution


    Oxidation number increases, oxygen gained and loss of electrons is oxidation.

  • Question 2
    1 / -0

    Reduction is defined in terms of

    I. electronation and hydrogenation
    II. deelectronation and gain of oxygen
    III. increase in oxidation number
    IV. decrease in oxidation number

    Select the correct terms

    Solution

    Gain of hydrogen , electron and decrease in oxidation number is reduction

  • Question 3
    1 / -0

    In balancing the half-reaction, CN→ CNO-

    The number of electrons that must be added is 

    Solution

    CN→ CNO-
    4+ x = -1      4+ x-2 = -1
    ∴ x = -5    ∴ x = -3   
    Oxidation number increases. This is oxidation.

    CN→ CNO- + 2e-

  • Question 4
    1 / -0

    Select the set of compounds with oxidation-reduction duality.

    Solution

    Com pounds having oxidising and reducing nature in given reaction are said to have oxidation-reduction duality. Such compounds are said to undergo disproportionation reaction.




    (This is called Cannizzaro reaction.)

    Note Such compounds have O.N. of the affected atoms intermediate of oxidation part and reduction part

  • Question 5
    1 / -0

    In the following balanced reaction,

    Solution

    If balanced, then to balance charge
    x = - 1

  • Question 6
    1 / -0

    I reduces IO3- and I2 and itself oxidised to I2 in acidic medium. Thus, final reaction is

    Solution


    To balance oxidation number, cross-multiply by change in oxidation number

  • Question 7
    1 / -0

    H2O can be oxidised to

    Solution


    H is reduced to H2 and O is oxidised to O2.

  • Question 8
    1 / -0

    Consider the following reactions,

    I. Zn + dil. H2SO4 → ZnSO4 + H2
    II. Zn + conc. H2SO4 → ZnSO4+ SO2 + H2O

    Oxidising agents in I and II are

            

    Solution


  • Question 9
    1 / -0

    In the following reactions except in one, oxygen is the reducing agent. Exceptional reaction is

    Solution


    Ag+ is reduced to Ag by oxygen



    Thus, except in (b), oxygen behaves as reducing agent.

  • Question 10
    1 / -0

    In the following reaction,

    Which ions are not balanced?

    Solution



    To balance electron  (II)  is to be multiplied by (3). Thus,

  • Question 11
    1 / -0


    Coefficient x, y and z are respectively 

    Solution


    Cross -multiply by change in oxidation number and balance H by H+ ions.

    Thus, x = 2, y = 5 and z = 6 

  • Question 12
    1 / -0

    Which of the following species does not show disproportionation reaction?

    Solution

    Maximum oxidation number of Cl = + 7

    Thus, species with + 7 oxidation number can be reduced but not oxidised.

  • Question 13
    1 / -0

    Which is the intramolecular oxidation-reduction reaction?

    Solution



  • Question 14
    1 / -0

    Consider the following experimental facts,

    I. When Cl2 gas is passed into Kl solution containing CHCI3, violet colour appears in CHCI3 layer.
    II. When Cl2 gas is passed into KBr solution containing CHCI3, orange colour appears in CHCI3 layer.
    III. When Cl2 gas is passed into a solution containing KBr, Kl and KCI, containing CHCI3, violet colour appears in CHCI3 layer.

    Select the correct experimental facts.

    Solution

    Oxidising power of F2 > CI2 > Br2 > l2


    Thus, (II) is true.

    In experiment (III), orange colour of Br2 does not appear, as it also oxidises Kl to l2. Hence , only violet colour appears in CHCI3 layer. Thus, (III) is also true.

  • Question 15
    1 / -0

    Based on the following reaction,

    It can be concluded that

    Solution


    Since, ΔG ° < 0, hence it is spontaneous in forward direction . Oxidation number of Xe decreases hence, it is an oxidising agent and oxidation number of F increases, hence it is a reducing agent.

  • Question 16
    1 / -0

    For the redox reaction,

    x, y and z are 

    Solution


    To balance a redox reaction , balance effected atoms

    II. Take oxidation number of two Cr-atom

    Take total (oxidation number) of each atom (oxidised, re duced ) cross - multiply by change in oxidation number and add
    I x 6 + II x 1

    Thus, x = 6
    y = 1
    z = 14

  • Question 17
    1 / -0

    In the following conversion of chromite into soluble chromium salt
    4Fe(CrO2)2+ 8Na2CO3 + 7O2 --> 2Fe2O3 + 8Na2CrO4 + 8CO2 

    There is 

    Solution


    Fe 2+ and Cr3+ are oxidised (increase in oxidation number)
    O2, is reduced .

  • Question 18
    1 / -0

    In which of the following reactions H2O2 acts as a reducing agent?




    Solution

    A species which is oxidised (deelectronation) is a reducing agent.

    Thus, (ii) and (iv) represent reducing behaviour of H2O2.

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