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Stoichiometry & Redox Reaction Test - 5

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Stoichiometry & Redox Reaction Test - 5
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  • Question 1
    1 / -0

    For Zn2+/Zn = - 0.76 V, Cl2/Cl- = 1.36 V, H+/1/2H2 = 0 V and Fe3+/Fe2+ = 0.77 V, the increasing order of strengths as a reducing agent is

    Solution

    The substances with a lower value of reduction potential are stronger reducing agents.

    Hence, the increasing order of the strengths as reducing agents is:

    Cl2, Fe3+, H2, Zn

     

  • Question 2
    1 / -0

    The oxidation potential values of A, B, C and D are -0.03 V, +0.108 V, -0.07 V and +0.1 V, respectively. The non-spontaneous cell reaction takes place between

    Solution

    Ecell = EReduction (cathode) - EReduction (anode)
    Or
    Ecell = EOxidation (anode) - EOxidation (cathode)
    A cell functions when Ecell is positive, i.e. when EReduction(cathode) > EReduction (anode) and EOxidation (anode) > E Oxidation (cathode).
    Since the order of oxidation potentials is: B > D > A > C.
    Therefore, the cell will not function when A is at anode and B is at cathode.

     

  • Question 3
    1 / -0

    The oxidation number of phosphorus in HP2O7-3 ion is

    Solution

    Oxidation number of phosphorus in HP2O7−3 ion is calculated as follows.
    1 + 2x - 14 = -3
    x = +5

     

  • Question 4
    1 / -0

    In which of the following reactions does H2O2 act as a reducing agent?

    Solution

    In the reaction Cl2 + H2O2 → 2HCl + O2, the oxidation number of oxygen changes from -1 to 0.
    Hence, H2O2 is oxidised by chlorine and it itself acts as a reducing agent.

     

  • Question 5
    1 / -0

    KMnO4 is a strong oxidising agent in the acidic medium. To provide acidic medium, H2SO4 is used instead of HCl. This is because

    Solution

    KMnO4 is a strong oxidising agent in acidic medium.
    H2SO4 is used instead of HCI to provide acidic medium because of HCI is oxidised by KMnO4 into CI2.

     

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