Solid State Test

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Solid State Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

If Z is the number of atoms in the unit cell that represents the closest packing sequence ABC ABC ABC _______, the number of tetrahedral voids in the unit cell is:

A
Z

B
2Z

C
Z/2

D
Z/4

Solution

Number of tetrahedral voids is double the total number of atoms.
ABC ABC pattern is followed in the ccp lattice and the unit cell is an fcc unit cell.
Therefore, Z is 4 and the number of tetrahedral voids is 8.
Question 2
1 / -0

Which set of characteristics of ZnS crystal is correct?

A
Coordination number (4 : 4); ccp; Zn²⁺ ions in alternate tetrahedral voids.

B
Coordination number (6 : 6); hcp; Zn²⁺ions in all tetrahedral voids.

C
Coordination number (6 : 4); hcp; Zn²⁺ions in all octahedral voids.

D
Coordination number (4 : 4); ccp; Zn²⁺ions in all tetrahedral voids.

Solution

ZnS has ccp arrangement. The S^2– ions are present at the corners of the cube and the centre of each face. Zinc ions occupy half of the tetrahedral sites and S^2- ions are surrounded by four Zn²⁺ ions.
Question 3
1 / -0

Which of the following statements are not true about hexagonal close packing?

(a) It has 26% empty space.
(b) In this arrangement, third layer is identical to the first layer.
(c) The coordination number in this arrangement is 6.
(d) It is as closely packed as body centred cubic packing.

A
a and b

B
c and d

C
a and d

D
a, b and c

Solution

A hexagonal close packing has coordination number 12 and is not as closely packed as bcc.
Question 4
1 / -0

For a metallic crystal having bcc type staking pattern, what percentage of the volume of its lattice is empty?

A
68%

B
32%

C
26%

D
74%

Solution

The bcc is having packing efficiency 68%. Thus, 32% space is empty.
Question 5
1 / -0

Choose the correct statement(s) from the following:

1. Frenkel and Schottky defects are thermodynamic defects.
2. Compounds with Schottky defects do not obey law of constant composition.
3. In compound with Frenkel defect, among a majority of metal ions of one valency, a few metal ions of another valency are also found.

A
1 only

B
2 only

C
1 and 2

D
1, 2 and 3

Solution

Frenkel and Schottky defects are thermodynamic defects. Schottky defect is a stoichiometric defect and it obeys law of constant composition.
Question 6
1 / -0

If NaCl is doped with 10^-4 mol% of SrCl₂, the concentration of cationic vacancies will be

A
6.022 x 10¹⁶ mol^-1

B
6.022 x 10¹⁷ mol^-1

C
6.022 x 10¹⁴ mol^-1

D
6.022 x 10¹⁵ mol^-1

Solution

On doping NaCl by SrCl₂, one Sr²⁺ ion replaces two Na⁺ ions.
So, number of moles of cation vacancy in 100 ml NaCl = 10^-4
Number of moles of cation vacancy in 1 mole NaCl = 10^-4/100 = 10^-6
Thus, total cation vacancy = 10^-6 x N_A= 10^-6 x 6.022 x 10²³ = 6.022 x 10¹⁷mol^-1
Question 7
1 / -0

Addition of CdCl₂ to AgCl yields a solid solution where divalent cations Cd²⁺occupy Ag⁺ sites. Which of the following statements is true?

A
The number of cationic vacancies is equal to that of divalent ions added.

B
The number of cationic vacancies is double that of divalent ions added.

C
The number of cationic vacancies is half that of divalent ions added.

D
No cationic or anionic vacancies are produced.

Solution

The number of cationic vacancies is equal to that of the divalent ions added as each divalent Cd²⁺ions replaces two monovalent Ag⁺ ions so that electrical neutrality of the crystal lattice is retained.
Hence, for every Cd⁺² ion there is one cationic vacancy.
Question 8
1 / -0

Non-stoichiometric metal deficiency is observed in the salts of

A
alkaline earth metals only

B
transition metals only

C
all metals

D
alkali metals

Solution

Non-stoichiometric metal deficiency is observed in the salts of transition metals because they possess variable valency.

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Solid State Test - 10

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Solid State Test - 10

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Question 1

Z

2Z

Z/2

Z/4

Solution

Question 2

Coordination number (4 : 4); ccp; Zn2+ ions in alternate tetrahedral voids.

Coordination number (6 : 6); hcp; Zn2+ ions in all tetrahedral voids.

Coordination number (6 : 4); hcp; Zn2+ ions in all octahedral voids.

Coordination number (4 : 4); ccp; Zn2+ ions in all tetrahedral voids.

Solution

Question 3

a and b

c and d

a and d

a, b and c

Solution

Question 4

68%

32%

26%

74%

Solution

Question 5

1 only

2 only

1 and 2

1, 2 and 3

Solution

Question 6

6.022 x 1016 mol-1

6.022 x 1017 mol-1

6.022 x 1014 mol-1

6.022 x 1015 mol-1

Solution

Question 7

The number of cationic vacancies is equal to that of divalent ions added.

The number of cationic vacancies is double that of divalent ions added.

The number of cationic vacancies is half that of divalent ions added.

No cationic or anionic vacancies are produced.

Solution

Question 8

alkaline earth metals only

transition metals only

all metals

alkali metals

Solution

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Coordination number (4 : 4); ccp; Zn²⁺ ions in alternate tetrahedral voids.

Coordination number (6 : 6); hcp; Zn²⁺ions in all tetrahedral voids.

Coordination number (6 : 4); hcp; Zn²⁺ions in all octahedral voids.

Coordination number (4 : 4); ccp; Zn²⁺ions in all tetrahedral voids.

6.022 x 10¹⁶ mol^-1

6.022 x 10¹⁷ mol^-1

6.022 x 10¹⁴ mol^-1

6.022 x 10¹⁵ mol^-1