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Solid State Test - 4

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Solid State Test - 4
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Weekly Quiz Competition
  • Question 1
    1 / -0

    In a compound, atoms of element Y forms ccp lattice and those of element X occupy 2/3rd of tetrahedral voids. The formula of the compound is:

    Solution

    Number of atoms of Y=4 

    Number of atoms of X=2/3*=16/3 

    Hence, X:Y=16/3:4 

    So, formula is X4Y3

     

  • Question 2
    1 / -0

    In a closed packed array of N spheres, the number of tetrahedral holes are:

    Solution

    If there are N closed spheres , then number of octahedral voids equals to N and number of tetrahedral voids equals to 2N

     

  • Question 3
    1 / -0

    The radius ratio of KF is 0.98. the structure of KF is similar to:

    Solution

    As the radius ratio is beyond 0.732, so the crystal structure is similar to CsCl.

     

  • Question 4
    1 / -0

    NH4Clcrystallizes in a body centred cubic lattice, with a unit cell distance of 387 pm. The distance between the oppositely charged ions in the lattice is:

    Solution

    In a body centred cubic lattice, oppositely charged ions touch each other along the cross-diagonal of the cube.So, we can write, 
    r+ + r- =3*a/2 
    r+ + r- =3*387/2 = 335.15 pm

     

  • Question 5
    1 / -0

    Which one of the following crystals does NOT exhibit Frenkel defect?

    Solution

    Frenkel defect occur due to movement of smaller cations into interstitial space due to larger difference in ionic radii of cations and anions. 
    AgBr, AgCl and ZnS exhibit frenkel defect.

     

  • Question 6
    1 / -0

    A compound XY crystallizes in BCC lattice with unit cell edge-length of 480pm, if the radius of Y- is 225pm, then the radius of X+ is:

    Solution

    For BCC lattice, 2(r+ + r-)=3a 
    r+=(3*480)-225 =190.7 pm

     

  • Question 7
    1 / -0

    All ferromagnetic materials become paramagnetic above a temperature called:

    Solution

    Ferromagnetic materials will lose their magnetism if heated above a point known as Curie temperature. At this point, the energy being put from heat will permanently disrupt magnetic domain structure of material, turning it into a paramagnetic material.

     

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