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Electrochemistry Test - 5

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Electrochemistry Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following is mostly used as a reference electrode?

    Solution

    The reference electrode is made by using Hg2Cl2.

     

  • Question 2
    1 / -0

    During the measurement of EMF of a half cell using a reference electrode and a salt bridge, if the salt bridge is removed, then the voltage

    Solution

    A salt bridge, in electrochemistry, is a laboratory device used to connect the oxidation and reduction half-cells of a galvanic cell. It maintains electrical neutrality within the internal circuit, preventing the cell from rapidly running its reaction to equilibrium. If no salt bridge were present, the solution in one half cell would accumulate negative charge and the solution in the other half cell would accumulate positive charge as the reaction proceeded, quickly preventing further reaction, and hence production of electricity.

    Hence, during the measurement of EMF of a half cell using a reference electrode and a salt bridge, if the salt bridge is removed, then the voltage drops to zero or becomes negative.

     

  • Question 3
    1 / -0

    Match Column–I with Column–II and indicate your answer by selecting the appropriate option.

    ColumnI ColumnII
    (A) Standard hydrogen electrode (a) Chemical equivalent/Faraday
    (B) Electrochemical equivalent (b) ΔGo < 0
    (C) E0 > 0 (c) Calibration of potentiometer
    (D) Weston cadmium cell (d) E0 = 0 at all temperatures
    Solution

    (A) Standard hydrogen electrode has E0 = 0 at all temperatures.
    So, (A) – (d)
    (B) Electrochemical equivalent = Chemical equivalent/Faraday
    So, (B) – (a)
    (C) E0 > 0 corresponds to ΔG0 < 0 as both indicate spontaneity of a cell reaction.
    So, (C) – (b)
    (D) Weston cadmium cell is a standard cell used to calibrate a potentiometer.
    So, (D) – (c)
    Answer: (A) – (d), (B) – (a), (C) – (b), (D) – (c)

     

  • Question 4
    1 / -0

    An electrochemical cell is represented as follows.

    Pt (H2, 1 atm) | 0.1 M HCl || 0.1 M acetic acid | (H2, 1 atm) Pt

    The emf of this cell will not be zero because the

    Solution

    The emf of this cell will not be zero because the pH values of 0.1 M HCl and 0.1 M acetic acid are not the same.

     

  • Question 5
    1 / -0

    Nernst equation E = Eo - (RT/nF) lnQ indicates that the equilibrium constant Kc will be equal to Q when

    Solution

    Nernst equation E = Eo - (RT/nF) lnQ
    At equilibrium: Kc = Q
    E = 0
    Therefore, Eo = (RT/nF)lnKc

     

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