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Isomerism Test - 17

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Isomerism Test - 17
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  • Question 1
    1 / -0

     Detection of nitrogen, sulphur, halogens and phosphorus in an organic compound is done by:

    Solution

    Nitrogen, Sulphur, and halogens present in organic compounds are detected by Lassaigne’s test. Here, a small piece of Na metal is heated in a fusion tube with the organic compound.

  • Question 2
    1 / -0

    In case both nitrogen and sulphur is present in an organic compound with sodium fusion extract a blood red colour is formed that is of:

    Solution

    If both nitrogen and sulphur are present in an organic compound, sodium fusion will convert it into sodium thiocyanate which then reacts with Fe3+ to form a blood colour complex [Fe(SCN)3​].

  • Question 3
    1 / -0

     When a compound is heated with copper(ii) oxide it is the test for?

    Solution

    • When a compound is heated with copper(ii) oxide it is the test for carbon.           
    • These are detected by heating the compound with copper(II) oxide. Carbon is oxidized to CO2 – confirmed by reaction with lime water that gives turbidity and turns limewater milky.
    • Hydrogen is oxidized to H2O – tested with anhydrous copper sulphate which turns blue.

    Hence, the correct answer is Option C.

  • Question 4
    1 / -0

     Laissaigne’s extract is made to:

    Solution

    The correct answer is option C
    The halogens, nitrogen and sulphur are covalently bonded to the organic compounds. In order to detect them, the elements need to be converted into their ionic forms. This is done by fusing the organic compound with sodium metal. The ionic compounds formed during the fusion are extracted in aqueous solution and can be detected by simple chemical tests. The extract is called sodium fusion extract or Lassaigne's extract.

  • Question 5
    1 / -0

     In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. The percentage of sulphur in the compound is:

    Solution

  • Question 6
    1 / -0

    A compound when treated with sodium peroxide and the solution is boiled with nitric acid and then treated with ammonium molybdate is the test for:

    Solution

    The phosphorus containing organic compound are detected by 'Lassaigne's test' by heated with an oxidizing agent (sodium peroxide)
    The phosphorus present in the compound in oxidised to phosphate.
    The solution is boiled with nitric acid and then treated with ammonium molybdate to produced canary yellow precipitate.
    Na3PO4 + 3HNO3 ⟶ H3PO4 + 3NaNO3 
    H3PO4 + 12(NH4)2MoO4 (Ammonium molybdate) + 21HNO3⟶(NH4)3PO4⋅12MoO3↓ + 21NH4NO3 + 12H2O

  • Question 7
    1 / -0

    The white precipitate which is formed in the detection of chloride ion is due to the formation of:

    Solution

     If silver nitrate solution is poured into a solution of sodium chloride, a chemical reaction occurs forming a white precipitate of silver chloride.

  • Question 8
    1 / -0

     In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. The percentage of bromine in the compound is:

    Solution

    Mass of Bromine = 80u

    Mass of AgBr = 188u

    Weight of AgBr = 0.12g
    Weight of organic compound = 0.15g

  • Question 9
    1 / -0

    A pale yellow precipitate soluble in ammonium hydroxide solution indicates the presence of:

    Solution

    The correct answer is option C
    A pale yellow precipitate soluble in ammonium Hydroxide solution indicates the presence of Bromine.

  • Question 10
    1 / -0

     In the test of nitrogen the Prussian blue color formed is of:

    Solution

    In Lassaigne's test for the detection of nitrogen in an organic compound, the appearance of a blue coloured compound is due to ferric ferrocyanide.
     
    In this test, sodium fusion extract is boiled with ferrous sulphate and then acidified with conc. sulphuric acid. Prussian blue colour complex ferric ferrocyanide confirms the presence of nitrogen.
    FeSO4+2NaOH→Fe(OH)2+Na2SO4
    6NaCN+Fe(OH)2→Na4Fe(CN)6+2NaOH
     
    3NaFe(CN)6+4FeCl3→Fe4[Fe(CN)6]3+12NaCl

    It is ferric ferrocyanide.

    Hence, the correct answer is Option D.

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