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Major Product
Major Product (A) is :
Product (B) will be :
(Major ) Product (A) will be :
Product (A) will be :
Mono-chloro product (inculding steroisomers)are :
Arrange the following in decreasing order of their boiling points
A) n-butaneB) 2-methylbutaneC) n-pentaneD) 2,2-dimethylpropane
D is the correct answer.The boiling point of alkanes increases with increase in molecular mass and for the same alkane, the boiling point decreases with branching. Thus, the decreasing order of their boiling points is: C B D n−Pentane>2−Methylbutane>2,2−Dimethylpropane> n−Butane A
products.Which of the following is not the free radical combination product in wurtz process.
Methyl cyclohexane react with Br2 in presence of u.v. light major product will be
Correct order of rate of reaction will be
Reactivity of Alkyl Halide for Wurtz RxnR - I > R - Br > R - Cl > R - F
Which of the gases evolved on the surface of anode.
Suitable reagent for following cenversion will be :
2, 3-dimethyl butaneWhich of the following anion will be migrates towards anode to prepare 2, 3-dimethyl butane in the given reaction.
Most stableconfomer of product will be (across C2 — C3 bond) :
[ Most Stable Conformer of h butane across C2 - C3 bond ]
most stableconfomer of product will be :
Most stable conformer of n - propane
Correct order of mono bromination of given compound is :
[ Most stable free radical is formed as intermidiate ] Order of Bromination = I > III > II >
major product will be
In kolbe’s electrolytic synthesis the pOH of solution will be
in Kolbe’s eledrolysis process. NaOH / KOH is Formed at cathod so PH increases and POH decrease
product will be :
Rate of decarboxylation of following carboxylic acid with sodalime will be in order
[rater of decorboxylation µ stability of corbanion]rate of decorboxylation = r1 > r2 > r3
Benzoic acid Product will be
Number of required O2 mole for complete combustion of one mole of propane-
How much volume of air will be needed for complete combustion of 10 lit. of ethane-
x mole oxygen are present in 5 x air22.4 liter ethan are Complete Combused to required 7/2 22.4 o2 gasRequired volume of air for complete combustion = 3 5×5 = 175 liter
Correct -
Wrong -
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