Hydrocarbons Te...

Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. How many different alkenes are formed when 2 -chlorobutane is treated with ethanolic solution of KOH? 

What is the major dehydration product in the following reaction ?

Which of the following compounds will lose optical activity after the reaction ?

In which of the following reactions , only single is omer of alkene is formed ?

Consider the following reaction .

The correct statement concerning product of the above reaction is 

An optically active hydrocarbon X has molecular formula C₆H₁₂. X on catalytic hydrogenation gives optically inactive C₆H₁₄. X could be

Which of the following reactions produces an alkene?

What is the major product of the reaction given below ?
meso -2 ,3 -dichiorobutane + Nal (aq) →

Direction (Q, Nos. 9 - 12) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q.

Statement I : 2-butyne on reduction with Pd/CaCO₃ gives c/s-2-butene.
Statement II : Hydrogenation proceed through adsorption mechanism.

Statement I : 2, 3-dibromo butane with Zn-dust gives frans-2-butene as major product.

Statement II : frans-2-butene is more stable than c/s-2-butene.

Statement I :  2-bromobutane with (CH₃)₃COK in tertiary butanol gives 1 -butene as major product.
Statement II : Very strong base (CH₃)₃COK in tertiary butanol brings about E-2 elimination reaction.

Statement I : Boiling point of an alkene is slightly greater than that of its hydrogenated alkane.
Statement II : Alkenes have stronger van der Waals’ force of attraction than alkanes.