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Carboxylic Acid & Derivatives Test - 15

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Carboxylic Acid & Derivatives Test - 15
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  • Question 1
    1 / -0

    Ethyl acetate is obtained when methyl magnesium bromide reacts with

    Solution

    Ethyl acetate is obtained when methyl magnesium bromide reacts with ethyl chloroformate.

     

  • Question 2
    1 / -0

    Saponification of ethyl benzoate with caustic soda as alkali gives

    Solution

     

  • Question 3
    1 / -0

    Electrolysis of aqueous solution of CH3​COOK gives

    Solution

     

  • Question 4
    1 / -0

    The reaction of HCOOH with conc. H2​SO4​ gives 

    Solution

     

  • Question 5
    1 / -0

    Carboxylic acids are more acidic than phenol and alcohol because of

    Solution

    Conjugate base of carboxylic acids i.e. carboxylate ion is resonance stabilised

     

  • Question 6
    1 / -0

    Carboxylic acids dimerise due to:

    Solution

    Due to the small size and strong hydrogen bonding between the molecule (intermolecular), they overlap and form a dimer in aqueous condition.

     

  • Question 7
    1 / -0

    Arrange the following in decreasing order of acidic strength.

    I. Benzoic acid
    II. 4-nitrobenzoic acid
    III. 3, 4-dinitrobenzoic acid
    IV. 4-methoxy benzoic acid

    Solution

    Since, electron donating groups decreases the acid strength, therefore, 4-methoxy benzoic acid is a weaker acid than benzoic acid. Further, since electron-withdrawing groups increase the acid strength, therefore, both 4-nitrobenzoic acid and 3, 4-dinitrobenzoic acid are stronger acid than benzoic acid.

    Further, due to presence of an additional NO2​ at m-position with respect to COOH group, 3, 4-dinitrobenzoic acid thus the overall acid strength increase in the order:

    4-methoxy benzoic acid < benzoic acid < 4-nitrobenzoic acid < 3, 4-dinitrobenzoic acid.

     

  • Question 8
    1 / -0

    When salicyclic acid is treated with acetic anhydride we get

    Solution

     

  • Question 9
    1 / -0

    Reaction of acetic anhydride with PCl5 gives

    Solution

    (CH3CO)2O + PCl5 → 2CH3COCl + POCl3

     

  • Question 10
    1 / -0

    Acetic acid reacts with chlorine in the presence of catalyst, anhydrous FeCl3​ to give:

    Solution

    Reaction:

     

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