Carboxylic Acid & Derivatives Test

Result

Carboxylic Acid & Derivatives Test - 17

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Weekly Quiz Competition

Question 1
1 / -0

Ethyl alcohol reacts with acetyl chloride to form

A
Ethyl chloride

B
Acetic acid

C
Methyl acetate

D
Ethyl acetate

Solution
Question 2
1 / -0

Acetic anhydride is obtained from acetyl chloride by the reaction of

A
P₂O₅

B
H₂SO₄

C
CH₃COONa

D
CH₃COOH

Solution
Question 3
1 / -0

Which of the following compounds on boiling with KMnO₄ (alk.) and subsequent acidification will not give benzoic acid?

A
Benzyl alcohol

B
Acetophenone

C
Anisole

D
Toluene

Solution

Anisole C₆H₅OCH₃ is not oxidised by KMnO₄ to benzoic acid
Question 4
1 / -0

The acid formed when propyl magnesium bromide is treated with CO₂is

A
C₃H₇COOH

B
C₂H₅COOH

C
both a and b

D
none of these

Solution
Question 5
1 / -0

Ethylalcohol on oxidation with K₂Cr₂O₇ gives

A
Acetic acid

B
Formic acid

C
Formaldehyde

D
Acetaldehyde

Solution

Ethyl alcohol on oxidation with K₂Cr₂O₇ gives Acetic acid.
Question 6
1 / -0

What will happen if LiAlH₄ is added to an ester

A
Two units of alcohol are obtained

B
One unit of alcohol and one unit of acid is obtained

C
Two units of acids are obtained

D
None of these

Solution

Two units of alcohol are obtained
Question 7
1 / -0

Which will not give acetamide on reaction with ammonia

A
Acetic acid

B
Acetyl chloride

C
Acetic anhydride

D
Methyl formate

Solution

a). Ammonia gas dissolves in water to form ammonium hydroxide, a base. Ammonium hydroxide then reacts with acetic acid to form ammonium acetate and water.

b). Acetyl chloride reacts violently with a cold concentrated solution of ammonia. A white solid product is formed which is a mixture of acetamide and ammonium chloride.

c). In the reaction between ethanoic anhydride and ammonia, the amide formed is called ethanamide.

when methyl formats and ammonia react it produce formamide; when water is present during this reaction a mixture of formamide and ammonium formate is obtained.
Question 8
1 / -0

Reduction of acetyl chloride with H₂in presence of Pd and BaSO₄ gives :

A
CH₃COCH₃

B
C₂H₅OH

C
CH₂COOH

D
CH₃CHO

Solution
Question 9
1 / -0

In the below reaction, product P is

A

B
C₆H₅ - CO - C₆H₅

C

D

Solution
Question 10
1 / -0

Acetic acid can be halogenated in presence of phosphorus and chlorine. Formic acid cannot be halogenated with same way because of:

A
presence of α−H atom in formic acid

B
presence of α−H atom in acetic acid

C
absence of α−H atom in CH₃COOH

D
higher acidic strength of acetic acid than formic acid.

Solution

HVZ reaction is given by only those carboxylic acids which have α−H atom. CH₃COOH has three α−H atoms but formic acid does not have α-hydrogen atom hence formic acid cannot be halogenated.