Carboxylic Acid & Derivatives Test

Result

Carboxylic Acid & Derivatives Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

A is

A

B

C
Both are correct

D
None is correct

Solution
Question 2
1 / -0

Lower carboxylic acid are soluble in water due to:

A
low molecular weight

B
hydrogen bonding

C
dissociation into ions

D
easy hydrolysis

Solution

Hydrogen bonds are formed between the individual molecules of the acid and water molecules.

It is because of these interactions that carboxylic acids can dissolve in water to form acidic solutions.

The carboxylic acids with low molar mass up to four carbon atoms are freely soluble in water.
Question 3
1 / -0

When propionic acid is treated with aqueous sodium bicarbonate, CO₂ is liberated. The C from CO₂ comes from:

A
methyl group

B
carboxylic acid group

C
methylene group

D
bicarbonate

Solution

When propionic acid is treated with aqueous sodium bicarbonate, CO₂ is liberated. The C from CO₂ comes from bicarbonate.
Question 4
1 / -0

Hydrolysis of an ester gives a carboxylic acid which on Kole's electrolysis yields ethane. the ester is

A
Methyl ethanoate

B
Ethyl amine

C
Ethyl methonoate

D
Propyl amine

Solution

Hydrolysis of methyl ethanoate yields Sodium Acetate which on Kolbe's electrolysis forms ethane as shown in the figure.
Question 5
1 / -0

Identify Z

A
CH₃CH₂CONH₂

B
CH₃COOH

C
CH₃CN

D
CH₃CH₂CONH₂

Solution

X is : CH₃CONH₂
Y is : CH₃C ≡ N
Z is : CH₃COOH
Question 6
1 / -0

Sulphonation of benzoic acid produces mainly

A
o- and p- Sulphobenzoic acid

B
o- Sulphobenzoic acid

C
m-Sulphobenzoic acid

D
p- Sulphobenoic acid

Solution
Question 7
1 / -0

Identify D

A
Amide

B
Primary amine

C
henyl isocyanate

D
Chain lengthed hydrocarbon

Solution
Question 8
1 / -0

Hydrolysis of an ester gives acid A and alcohol B. The acid reduces Fehling's solution. Oxidation of alcohol B gives acid A. The ester is

A
ethyl formate

B
methyl acetate

C
methyl formate

D
ethyl acetate

Solution

HCOOH is reducing agent
Question 9
1 / -0

Hydrated oxalic acid contains:

A
two water molecules

B
three water molecules

C
four water molecules

D
five water molecules

Solution

The formula of oxalic acid is (C₂H2O₄); its usual form is that of the crystalline hydrate, (COOH)₂⋅2H₂O.
Question 10
1 / -0

Acetyl bromide reacts with excess of CH₃MgI followed by treatment with a saturated solution of NH₄Cl gives:

A
acetone

B
acetamide

C
2-methyl-2-propanol

D
acetyl iodide

Solution

Acetyl bromide reacts with excess of CH₃MgI followed by treatment with a saturated solution of NH₄Cl gives tertiary alcohol which in the given option is : 2-methyl-2-propanol.