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Biomolecules Test - 10

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Biomolecules Test - 10
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  • Question 1
    1 / -0

    Glycogen is a branched chain polymer of α-D-glucose units in which chain is formed by C1—C4 glycosidic linkage whereas branching occurs by the formation of C1-C6 glycosidic linkage. Structure of glycogen is similar to ______.

    Solution

    Glycogen is a branched chain polymer of αD glucose units in which chain is formed by C1−C4 glycosidic linkage whereas branchin occurs by the formation of C1−C6 glycosidic linkage. Structure of glycogen can be shown below similar to the sturcture amplopectin.

  • Question 2
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    Which of the following polymer is stored in the liver of animals?

    Solution

    If blood glucose levels become too low, glucagon (pancreatic hormone) is released, which causes the liver to convert the stored glycogen back into glucose, and release it into the bloodstream.

  • Question 3
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    Sucrose (cane sugar) is a disaccharide. One molecule of sucrose on hydrolysis gives _________.

  • Question 4
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    Proteins are found to have two different types of secondary structures viz. α-helix and β-pleated sheet structure. α-helix structure of protein is stabilised by :

    Solution

    In α-helix, hydrogen bonds are present between –NH group of one amino acid residue to the >C= O group of another aminoacid residue.

  • Question 5
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    Which of the following is NOT a culinary use of oil in the food industry?

    Solution

     Flavor, texture and shortening are all major culinary uses of oil in the food industry.

  • Question 6
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    Dinucleotide is obtained by joining two nucleotides together by phosphodiester linkage. Between which carbon atoms of pentose sugars of nucleotides are these linkages present?

    Solution

    The correct answer is option A
    Nucleotides are joined together by phosphodiester linkage between 5′ and 3′ carbon atoms of pentose sugar.
     

  • Question 7
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    Nucleic acids are the polymers of ______________.

    Solution

    Nucleotides are organic molecules that serve as the monomer units for forming the nucleic acid polymers deoxyribonucleic acid and ribonucleic acid, both of which are essential biomolecules within all life-forms on Earth.

  • Question 8
    1 / -0

    Which of the following statements is not true about glucose?

    Solution

    The correct answer is Option C.
    Glucose is an aldohexose having structural formula.

    Glucose on heating with HI produces n hexane.
    C6H12O6 --HI→C6H14
    Glucose does not give 2,4. DNP test due to its existence as cyclic structure shown below :

    It is present in pyranose form, as shown below 

    Pyranose means pyran (membered ring containing oxygen) like structure.

  • Question 9
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    Each polypeptide in a protein has amino acids linked with each other in a specific sequence. This sequence of amino acids is said to be ____________.

    Solution

    The primary structure of a protein refers to the sequence of amino acids in the polypeptide chain. The primary structure is held together by peptide bonds that are made during the process ofprotein biosynthesis.

  • Question 10
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    DNA and RNA contain four bases each. Which of the following bases is not present in RNA?

    Solution

    Thymine is one of the four nucleobases in the nucleic acid of DNA that are represented by the letters G–C–A–T. The others are adenine, guanine, and cytosine. Thymine is also known as 5-methyluracil, a pyrimidine nucleobase. In RNA, thymine is replaced by the nucleobase uracil.

  • Question 11
    1 / -0

    Which of the following B group vitamins can be stored in our body?

    Solution

    The correct answer is option  D
    Vitamin B12
    The body has a limited capacity to store most of the B-group vitamins except B12 and folate, which are stored in the liver.

  • Question 12
    1 / -0

    Which one of the following bases is not present in DNA?

    Solution

    Quinoline is an alkaloid, it is not present in DNA. DNA  has four nitrogen bases in adenine, guanine, cytosine and  thymine

  • Question 13
    1 / -0

    Three cyclic structures of monosaccharides are given below which of these are anomers.
      

    Solution

    Structures (I and II) differ only in the position of OH at Cand hence are anomers. 

  • Question 14
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    Which of the following reactions of glucose can be explained only by its cyclic structure?

    Solution

    Due to absence of free OH group at Ccyclic structure of glucose pentacetate cannot revert to open chain aldehydic form and hence cannot form an oxime. 

  • Question 15
    1 / -0

    Optical rotations of some compounds along with their structures are given below which of them have D configuration.

    Solution

    The correct answer is Option A.
     
    I, II and III structures have D configuration with -OH group on the lowest asymmetric carbon is on the right side which is comparable to (+) glyceraldehyde.

  • Question 16
    1 / -0

    Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.

    Solution

    The correct answer is option C
    'a' carbon of glucose and 'b' carbon of fructose
    Carbon adjacent to the oxygen atom in the cyclic structure of glucose or fructose is known as anomeric carbon. As shown in the structure above ‘a’ and ‘b’ are present adjacent to an oxygen atom. Both carbons differ in configurations of the hydroxyl group.

  • Question 17
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    Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between C1 and C4 and which linkages are between C1 and C6?

     

    Solution

    The correct answer is Option C.

    (i)   The first structure is lactose, the linkage is (A) C1−C4 glycosidic linkage.
    (ii)  The 2nd structure has C1−C6 linkages.
    (iii) The 3rd structure has C1−C4 linkages.

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