Biomolecules Test

Result

Biomolecules Test - 6

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which among the following structures regarding the tertiary structure of proteins is incorrect?

A
The linear sequence of polypeptide chain is folded into compact globular structure.

B
The folding of the polypeptide chain is stabilised by strong non covalent interactions.

C
Electrostatic interactions are present between charged amino acid chains.

D
Hydrogen bonds are present in tertiary structure of proteins.

Solution

The folding of the polypeptide chain is stabilised by weak non covalent interactions.
Question 2
1 / -0

Directions For Questions

The following question has four choices, out of which ONLY ONE is correct.

...view full instructions

If three amino acids are combined, how many peptide linkages will be there and what will be the product?

A
One peptide linkage and the product will be dipeptide

B
Two peptide linkages and the product will be dipeptide

C
Three peptide linkages and the product will be tripeptide

D
Two peptide linkages and the product will be tripeptide

Solution

This option is correct because if three amino acids are combined, there will be two peptide linkages between them, and the product will be tripeptide because it is made up of three amino acids.
Question 3
1 / -0

Directions For Questions

The following question has four choices, out of which ONLY ONE is correct.

...view full instructions

A carbohydrate "A" containing 42.1% C and 6.4% H does not show any reducing property.
On hydrolysis with dil. HCl, a mixture of two isomeric substances "B" and "C" each containing 40% C and 6.67% H are produced.
''B'' reduces Fehling's solution and produces a yellow crystalline compound with excess phenylhydrazine.
''C'' does not reduce Fehling's solution but produces the same yellow crystalline solid with excess phenylhydrazine.

"A" may be

A
maltose

B
cellobiose

C
sucrose

D
Lactose

Solution

Formula of "A" = C : H : O = 42.1/12 : 6.4/1 : 51.5/16 = 3.51 : 6.4 : 3.22 = 11.99 : 21.89 : 11 = 12 : 22 : 11
So, "A" is C₁₂H₂₂O₁₁.

All the alternatives have the same molecular formula. Sucrose does not have reducing property. So, "A" is sucrose and option (3) is correct.

On hydrolysis with dil. HCl, a mixture of "B" (glucose) and "C" (fructose) is formed. Glucose reduces Fehling's solution and produces a yellow crystalline compound (osazone) with excess phenylhydrazine. Fructose does not reduce Fehling's solution but produces the same osazone with excess phenylhydrazine.
Question 4
1 / -0

Directions For Questions

The following question has four choices, out of which ONLY ONE is correct.

...view full instructions

A carbohydrate "A" containing 42.1% C and 6.4% H does not show any reducing property. On hydrolysis with dil. HCl, a mixture of two isomeric substances "B" and "C" each containing 40% C and 6.67% H produces. ''B'' reduces Fehling`s solution and produces a yellow crystalline compound with excess phenylhydrazine. ''C'' does not reduce Fehling`s solution but produces the same yellow crystalline solid with excess phenylhydrazine.

"B" may be

A
mannose

B
glucose

C
galactose

D
fructose

Solution

Formula of B = C : H : O = 40/12 : 6.67/1 : 53.33/16 = 3.33 : 6.67 : 3.33 = 1 : 2 : 1
So, empirical formula = CH₂O
Molecular formula = (CH₂O)_n
All the alternatives given have the formula = (CH₂O)₆ = C₆H₁₂O₆.
Glucose has reducing properties and can be obtained by the hydrolysis of cane sugar.