Gaseous States Test

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Gaseous States Test - 15

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Question 1
1 / -0

At moderate pressure, compressibility factor of gas

A
Increases with increase in temperature

B
Decreases with increase in temperature

C
Remains constant with change in temperature

D
Is less than one

Solution
Question 2
1 / -0

At very low pressures, the compressibility factor of CO₂ having constant value of molar volume

A
increases with increase in temperature

B
decreases with increase in temperature

C
remains constant with change in temperature

D
is one.

Solution
Question 3
1 / -0

Equal masses of methane and oxygen are mixed in an empty container at 25^∘C. The fraction of the total pressure exerted by oxygen will be:

A
1/2

B
2/3

C

D
1/3

Solution

Equal masses of methane and oxygen are mixed in an empty container at 25^oC. The fraction of the total pressure exerted by oxygen is 1/3.

Let 32 g of oxygen are mixed with 32 g of methane.

The molar masses of methane and oxygen are 16 g/mol and 32 g/mole respectively

The mole fraction is proportional to the fraction of the total pressure exerted.

Hence, the fraction of the total pressure exerted by oxygen is 1/3.
Question 4
1 / -0

In an experiment during the analysis of a carbon compound, 145 cm³ of H₂ was collected at 760 mmHg pressure and 27°C temperature. The mass of H₂ is nearly

A
10 mg

B
12 mg

C
24 mg

D
6 mg

Solution

calculate volume at STP

at STP 22400 cc=1 mole , number of moles = 132/22400

and mass = molecular weight × number of moles = 12 mg
Question 5
1 / -0

What is the ratio of mean speed of an O₃ molecule to the rms speed of an O₂ molecule at the same T?

A
(3π/7)^1/2

B
(16/9π)^1/2

C
(3π)^1/2

D
(4π/9)^1/2

Solution
Question 6
1 / -0

The compressibility of a gas is less than unity at STP, therefore:

A
V_m > 22.4 L

B
V_m < 22.4 L

C
V_m = 22.4 L

D
V_m = 44.8 L

Solution
Question 7
1 / -0

The total kinetic energy of 0.6 mol an ideal gas at 27⁰C is

A
1681 J

B
2245 J

C
1122 J

D
2806 J

Solution
Question 8
1 / -0

In van der Waals equation of state, the constant b is a measure of

A
volume occupied by the molecules.

B
intermolecular attraction.

C
intermolecular repulsion.

D
intermolecular collisions per unit volume.

Solution

In van der Waals equation of state, the constants a and b represent the magnitude of intermolecular attraction and excluded volume respectively and are specific to a particular gas. The constant b is a measure of the volume occupied by the molecules.
Question 9
1 / -0

The term that corrects for the attractive forces present in a real gas in the van der Waals equation is:

A
nb

B

C

D
−nb

Solution

The Van der Waals equation for real gas is given as,

Where P is Pressure

V is Volume

T is Temperature

n is the number of moles

a and b are constants.

R is the universal gas constant.

The term that corrects for the attractive forces present in a real gas in the Van der Waals equation is
Question 10
1 / -0

The critical temperature of water is higher than that of O₂ because the H₂O molecule has:

A
fewer electrons than O₂

B
two covalent bonds

C
V-shape

D
dipole moment

Solution

Higher are the intermolecular forces of attraction, higher will be the critical temperature.
Water is a polar molecule and has dipole moment. Strong dipole-dipole interaction are present in between water molecules.
Oxygen do not have dipole moment.
Hence the critical temperature of water is higher than that of oxygen.