Gaseous States Test

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Gaseous States Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

A mixture of N₂ and Ar gases in a cylinder contains 7g of N₂ and 8g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N₂ is :

[Use atomic masses (in g mol^-1) : N = 14, Ar = 40]

A
15 bar

B
18 bar

C
9 bar

D
12 bar

Solution
Question 2
1 / -0

A gas at 350K and 15 bar has molar volume 20% smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z)is:

A
Z>1 and attractive forces are dominant

B
Z>1 and repulsive forces are dominant

C
Z<1 and attractive forces are dominant

D
Z<1 and repulsive forces are dominant

Solution

Compressibility factor (Z) = V_real/ V_ideal

∵ V_real< V_ideal; Hence Z<1

⇒ If Z<1, attractive forces are dominant among gaseous molecules and liquefaction of gas will be easy.
Question 3
1 / -0

Given van der Waals constant for NH₃,H₂,O₂ and CO₂ are respectively 4.17,0.244,1.36 and 3.59, which one of the following gases is most easily liquefied?

A
O₂

B
NH₃

C
CO₂

D
H₂

Solution

Critical temperature ∝ van der Waal constant 'a'

Maximum 'a'⇒ gas with maximum T_C ⇒ easiest liquification = NH₃
Question 4
1 / -0

When helium is allowed to expand into vacuums, heating effect is observed. Its reason that

A
Helium is an ideal gas

B
Helium is an inert gas

C
The inversion temperature of helium is very low

D
The boiling point of helium is the lowest among the elements

Solution

A gas shows cooling effect on expansion only if it is carried out at temp. below a particular temp. ( called inversion temp. ) , since heating effect is observed, inversion temperature of helium is low
Question 5
1 / -0

One gram molecule of any gas at NTP occupies 22.4 L. This fact was derived from:

A
Dalton's theory

B
Avogardro's hypothesis

C
Berzelius hypothesis

D
Law of gaseous volume

Solution

According to Avogadro's law, 1 mole of every gas occupies 22.4L at NTP.

From ideal gas equation,

PV = nRT. . . . . . .(1)

At NTP,

T = 273K

P = 1atm

n = 1

R = 0.0821 atmL/Kmol

from equation (1),

V = P
Question 6
1 / -0

Vibrational energy is

A
Partially potential and partially kinetic

B
only potential

C
only kinetic

D
none of the above

Solution

Vibrational energy=K.E. + P.E
Question 7
1 / -0

According to kinetic theory of gases, the energy per mole of a gas is equal to

A
1.5RT

B
RT

C
0.5RT

D
2.5RT

Solution

According to kinetic theory of gases, the energy per mole of a gas is equal to 1.5RT.
Question 8
1 / -0

Which of the following is valid at absolute zero

A
Kinetic energy of the gas becomes zero but the molecular motion does not become zero

B
Kinetic energy of the gas becomes zero and molecular motion also becomes zero

C
Kinetic energy of the gas decreases but does not become zero

D
Kinetic energy of the gas is maximum

Solution

Kinetic Energy is directly proportional to temperature. With increase in temperature, kinetic energy increases. Consequently, the movement of the particles gets faster. Reverse phenomena is observed with decrease in temperature. At Absolute Zero temperature (−273.15°C), all the molecules are expected to have no kinetic energy and hence no molcecular motion. Absolute Zero is a theoretical value (it has never been reached).
Question 9
1 / -0

Kinetic energy of a gas depends upon its:

A
Molecular mass

B
Atomic mass

C
Equivalent mass

D
None of these

Solution

Kinetic energy = 3/2 RT
Question 10
1 / -0

Which is not true in case of an ideal gas?

A
It cannot be converted into a liquid.

B
There is no interaction between the molecules.

C
All molecules of the gas move with same speed.

D
At a given temperature, PV is proportional to the amount of the gas.

Solution

Molecules in an ideal gas move with different speeds. Due to collision between the particle their speed changes.

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Gaseous States Test - 4

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Gaseous States Test - 4

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Question 1

15 bar

18 bar

9 bar

12 bar

Solution

Question 2

Z>1 and attractive forces are dominant

Z>1 and repulsive forces are dominant

Z<1 and attractive forces are dominant

Z<1 and repulsive forces are dominant

Solution

Question 3

O2​

NH3​

CO2

H2

Solution

Question 4

Helium is an ideal gas

Helium is an inert gas

The inversion temperature of helium is very low

The boiling point of helium is the lowest among the elements

Solution

Question 5

Dalton's theory

Avogardro's hypothesis

Berzelius hypothesis

Law of gaseous volume

Solution

Question 6

Partially potential and partially kinetic

only potential

only kinetic

none of the above

Solution

Question 7

1.5RT

RT

0.5RT

2.5RT

Solution

Question 8

Kinetic energy of the gas becomes zero but the molecular motion does not become zero

Kinetic energy of the gas becomes zero and molecular motion also becomes zero

Kinetic energy of the gas decreases but does not become zero

Kinetic energy of the gas is maximum

Solution

Question 9

Molecular mass

Atomic mass

Equivalent mass

None of these

Solution

Question 10

It cannot be converted into a liquid.

There is no interaction between the molecules.

All molecules of the gas move with same speed.

At a given temperature, PV is proportional to the amount of the gas.

Solution

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O₂

NH₃

CO₂

H₂